Electrical and Electronics Measurements MCQ Quiz - Objective Question with Answer for Electrical and Electronics Measurements - Download Free PDF

Last updated on May 30, 2025

Latest Electrical and Electronics Measurements MCQ Objective Questions

Electrical and Electronics Measurements Question 1:

What determines the length of the delay in an electrical delay line used in
oscilloscopes?

  1. The propagation speed of the signal in the line
  2. The resistance of the delay line
  3. The frequency of the input signal
  4. The speed of the electron beam

Answer (Detailed Solution Below)

Option 1 : The propagation speed of the signal in the line

Electrical and Electronics Measurements Question 1 Detailed Solution

The correct answer is: 1) The propagation speed of the signal in the line

Explanation:

In an electrical delay line used in oscilloscopes, the delay time is determined by:

  • The physical length of the delay line

  • The propagation speed of the signal through the line (which depends on the medium's properties, such as its dielectric constant and inductance/capacitance per unit length).

Option Analysis

  1. The resistance of the delay line → Affects signal attenuation, not the delay time.

  2. The frequency of the input signal → The delay line is typically designed to be frequency-independent for a wide range of signals.

  3. The speed of the electron beam → This relates to the CRT display, not the delay line.

Thus, the correct choice is 1) The propagation speed of the signal in the line.

Electrical and Electronics Measurements Question 2:

The time delay in an oscilloscope can be measured by:

  1. measuring the time between two successive peaks of the signal
  2. measuring the amplitude of the signal
  3. counting the number of weak signals
  4. measuring the decibel of the signal

Answer (Detailed Solution Below)

Option 1 : measuring the time between two successive peaks of the signal

Electrical and Electronics Measurements Question 2 Detailed Solution

Explanation:

Measuring Time Delay in an Oscilloscope

Definition: An oscilloscope is an electronic instrument used to measure and visualize varying electrical signals. It displays the waveform of the signal, allowing for analysis of its properties such as amplitude, frequency, and time delay. The time delay in an oscilloscope refers to the interval between specific points in the waveform, such as between peaks or zero crossings.

Working Principle: Oscilloscopes work by sampling the input signal and plotting it on a screen as a function of time. The horizontal axis represents time, while the vertical axis represents the signal’s amplitude. By analyzing the waveform, one can measure various parameters, including the time delay.

Correct Option Analysis:

The correct option is:

Option 1: Measuring the time between two successive peaks of the signal.

To measure the time delay in an oscilloscope, the most straightforward and accurate method is to observe the time interval between two successive peaks of the signal. This approach utilizes the waveform's visual representation to determine the period or frequency of the signal. By identifying the time difference between consecutive peaks, one can accurately measure the time delay.

Additional Information

To further understand the analysis, let’s evaluate the other options:

Option 2: Measuring the amplitude of the signal.

This option is incorrect for measuring time delay. The amplitude of the signal refers to its strength or magnitude, not the time interval between points in the waveform. While amplitude is an important parameter, it does not provide information about the time delay.

Option 3: Counting the number of weak signals.

This option is also incorrect. Counting the number of weak signals does not relate to measuring time delay. Weak signals might refer to low amplitude portions of the waveform, but this does not help in determining the time interval between specific points in the signal.

Option 4: Measuring the decibel of the signal.

This option is incorrect as well. Decibels are a unit of measurement for the intensity of the signal, typically used in audio and sound engineering. Measuring the decibel level of the signal does not provide information about the time delay.

Conclusion:

Understanding the correct method to measure time delay in an oscilloscope is crucial for accurate signal analysis. By measuring the time between two successive peaks of the signal, one can effectively determine the time delay. Other options such as measuring amplitude, counting weak signals, or measuring decibels do not provide the necessary information for time delay measurement. Proper analysis and understanding of the waveform are essential for utilizing an oscilloscope effectively in various applications.

Electrical and Electronics Measurements Question 3:

Why is shielding used in oscilloscope probes?

  1. To control the electron beam in the oscilloscope
  2. To reduce external electromagnetic interference
  3. To increase the probe’s sensitivity
  4. To amplify weak signals

Answer (Detailed Solution Below)

Option 2 : To reduce external electromagnetic interference

Electrical and Electronics Measurements Question 3 Detailed Solution

Explanation:

Why is shielding used in oscilloscope probes?

Definition: Shielding in oscilloscope probes refers to the use of conductive materials to encase the probe and its components to protect against external electromagnetic interference. This interference, often coming from various electronic devices and environmental factors, can adversely affect the accuracy and reliability of measurements taken by the oscilloscope.

Working Principle: Shielding works on the principle of electromagnetic compatibility (EMC). It ensures that the probe is less susceptible to external electromagnetic fields, thereby maintaining the integrity of the signal being measured. The shielding typically involves a conductive material, such as metal, which encloses the probe and acts as a barrier to electromagnetic interference.

Correct Option Analysis:

The correct option is:

Option 2: To reduce external electromagnetic interference.

This option correctly describes the primary purpose of shielding in oscilloscope probes. The shielding effectively minimizes the impact of external electromagnetic interference, ensuring that the oscilloscope provides accurate and reliable measurements.

Additional Information

To further understand the analysis, let’s evaluate the other options:

Option 1: To control the electron beam in the oscilloscope.

This option is incorrect because shielding is not used to control the electron beam in the oscilloscope. The electron beam is controlled by the internal components of the oscilloscope, such as the electron gun and deflection plates, which direct the beam to create the visual representation of the signal on the screen.

Option 3: To increase the probe’s sensitivity.

This option is also incorrect. While shielding can help improve the accuracy of measurements by reducing interference, it does not directly increase the sensitivity of the probe. The sensitivity of an oscilloscope probe is determined by its design and the quality of its components.

Option 4: To amplify weak signals.

This option is incorrect as well. Shielding does not amplify signals. Signal amplification is typically achieved through the use of amplifiers within the oscilloscope or external amplifier circuits. Shielding is solely for the purpose of reducing interference.

Electrical and Electronics Measurements Question 4:

Which of the following instruments typically has the highest resolution?

  1. Digital multimeter
  2. Oscilloscope
  3. Digital thermometer
  4. Analog voltmeter

Answer (Detailed Solution Below)

Option 1 : Digital multimeter

Electrical and Electronics Measurements Question 4 Detailed Solution

The correct answer is: 1) Digital multimeter

Explanation:

Resolution in Measurement Instruments

Resolution refers to the smallest change in a measured quantity that an instrument can detect and display.

Comparison of Instruments:

Instrument Typical Resolution Key Notes
Digital Multimeter (DMM) 0.1 μV to 1 mV (e.g., 6½-digit DMM can resolve 1 μV on a 1 V range) Highest resolution due to precision analog-to-digital conversion and specialized circuitry.
Oscilloscope 1 mV to 10 mV (vertical scale) Optimized for speed, not ultra-fine voltage resolution.
Digital Thermometer 0.1°C (for standard models) Limited by sensor (e.g., thermocouple/RTD) and ADC resolution.
Analog Voltmeter 1% of full scale (e.g., 10 mV on a 1 V scale) Limited by parallax errors and mechanical movement.

Electrical and Electronics Measurements Question 5:

In a CRT oscilloscope, the horizontal deflection plates are used to:

  1. focus the beam on the phosphor screen
  2. create a sweeping movement of the beam from left to right
  3. control the electron gun
  4. display the vertical signal

Answer (Detailed Solution Below)

Option 2 : create a sweeping movement of the beam from left to right

Electrical and Electronics Measurements Question 5 Detailed Solution

The correct answer is: 2) Create a sweeping movement of the beam from left to right

Explanation:

In a CRT (Cathode Ray Tube) oscilloscope:

  • Horizontal deflection plates are responsible for moving the electron beam left to right (and back) in a controlled sweep. This generates the timebase (X-axis) of the displayed waveform.

  • The sweep can be triggered (for stable displays) or free-running (for repetitive signals).

Option Analysis

  1. Focus the beam → This is done by the focusing anode, not the deflection plates.

  2. Control the electron gun → The electron gun emits the beam, but deflection plates only steer it.

  3. Display the vertical signal → The vertical deflection plates (Y-axis) handle this, not the horizontal plates.

Thus, the correct choice is 2)

Top Electrical and Electronics Measurements MCQ Objective Questions

The type of damping use for moving iron instruments is ______.

  1. Air friction damping
  2. Fluid friction damping
  3. Eddy current damping
  4. Gravity friction damping

Answer (Detailed Solution Below)

Option 1 : Air friction damping

Electrical and Electronics Measurements Question 6 Detailed Solution

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M.C. Instruments

M.I. Instruments

1. MC type instruments are more accurate.

1. MI type are less accurate than MC type.

2. Manufacturing cost is high.

2. Cheap in cost.

3. Reading scale is uniformly distributed.

RRB JE EE 2 9Q 14th Dec 2014 Shift 2 Red(Hindi) - Final images Q3

3. Non-uniform scale

(scale cramped at beginning and finishing)

RRB JE EE 2 9Q 14th Dec 2014 Shift 2 Red(Hindi) - Final images Q3a

4. Very sensitive in construction & for input.

4, Robust in construction.

5. Low power consumption

5. Slightly high-power consumption.

6. Eddy current damping is used.

6. Air friction damping is used.

7. Can be used only for D.C measurements.

7. Can be used for A.C as well as for D.C measurements.

8. Controlling torque is provided by spring.

8. Controlling torque is provided by gravity or spring

9. Deflection is proportional to current. (θ α l).

9. Deflection is proportional to the square of the current.

(θ α l2).

10. Errors are set due to the ageing of control

springs. Permanent magnet (i.e. No Hysteresis loss).

10. Errors are set due to hysteresis and stray fields.

(i.e. hysteresis loss takes place).

Ammeter provides the path for:

  1. Maximum voltage
  2. Minimum voltage
  3. Minimum current
  4. Maximum current

Answer (Detailed Solution Below)

Option 4 : Maximum current

Electrical and Electronics Measurements Question 7 Detailed Solution

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Ammeter:

  • It is used to measure the current.
  • An ideal ammeter has zero internal resistance and thus it provides the path for maximum current.
  • It is always connected in series as it measures current.
  • The range of ammeter can be extended by using a low shunt resistance.


Voltmeter:

  • It is used to measure the voltage.
  • An ideal voltmeter has infinite resistance and thus it provides the path for minimum current.
  • It is always connected in parallel as it measures voltage.
  • The range of voltmeter can be extended by using a high series resistance.

A meter reads 125 V and the true value of the voltage is 125.5 V. Find the static error of the instrument.

  1. 125/0.5 V
  2. 125 V
  3. 0.5 V
  4. 0.5 / 125 V

Answer (Detailed Solution Below)

Option 3 : 0.5 V

Electrical and Electronics Measurements Question 8 Detailed Solution

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Concept:

Absolute Error: The deviation of the measured value from the true value (or) actual value is called error. It is also known as a static error.

Static error (E) = Am – At

Am = Measured value

At = True value

Relative Static Error: The ratio of absolute error to the true value is called relative static error.

\(R.S.E = \frac{{\left| {{A_m} - {A_t}} \right|}}{{{A_t}}} \times 100\)

Limiting Error:

The maximum allowable error in the measurement is specified in terms of true value, is known as limiting error. It will give a range of errors. It is always with respect to true value, so it is a variable error.

Guaranteed Accuracy Error:

The allowable error in measurement is specified in terms of full-scale value is known as a guaranteed accuracy error. It is a variable error seen by the instrument since it is with respect to full-scale value.

Application:

Given-

Am = 125 V, At = 125.5 V

∴ Static error (E) = 125 - 125.5

E = 0.5 V

When the pointer of an indicating instrument is in motion, then the deflecting torque is opposed by:

  1. Damping torque
  2. Controlling torque
  3. Both damping torque and controlling torque
  4. Rotating torque

Answer (Detailed Solution Below)

Option 2 : Controlling torque

Electrical and Electronics Measurements Question 9 Detailed Solution

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The essential features are possessed by an indicating instrument deflecting, controlling, and a damping device.

  • Deflecting device: The deflection device produces deflecting torque which causes the moving system to move from its zero position.
  • Controlling device: The controlling device produces the controlling torque (Tc) which opposes the deflecting torque and increases with the deflection of the moving system. It also brings the pointer back to zero when the deflecting torque is removed.
  • Damping device: This device produces damping torque this torque is necessary to bring the pointer to rest quickly. This damping torque (Td)  is used to reduce the oscillation.

A galvanometer is used to ________

  1. detect the direction of light
  2. detect the direction of current
  3. detect the direction of magnetic induction
  4. detect the direction of sound

Answer (Detailed Solution Below)

Option 2 : detect the direction of current

Electrical and Electronics Measurements Question 10 Detailed Solution

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  • A Galvanometer is used to detect the direction of the current.
  • This device is used for detecting and measuring a small amount of electric current.
  • Johann Schweigger invented the device in 1820.
     

Measuring Instrument

Quantity

Photometers

Light

Magnetometer

Magnetic induction

Sound Level Meter

sound

More power is required to operate a moving-iron meter than a PMMC meter because of the magnetic circuit's high _____.

  1. resistance
  2. reluctance
  3. retentivity
  4. resilience

Answer (Detailed Solution Below)

Option 2 : reluctance

Electrical and Electronics Measurements Question 11 Detailed Solution

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Moving iron meter has large magnetic reluctance as compared to PMMC meter. That’s why more power is required to operate the moving iron meter.

Advantages of moving iron:

  • It is a universal instrument which can be used for the measurement of AC and DC quantities
  • These instruments can withstand large loads and are not damaged even under severe overload conditions
  • It is very cheap due to the simple construction

 

Disadvantages of moving iron:

  • These instruments suffer from error due to hysteresis, frequency change and stray losses
  • The reading of the instrument is affected by temperature variation

 

Note: In terms of accuracy PMMC meter has the highest accuracy. The order of accuracy is given below.

Induction < Moving iron < PMMC instruments

If a 100 watts bulb is used for 10 hours, then the amount of consumed electrical energy will be -

  1. 100 Watts
  2. 100 Watts per hour
  3. 1000 Watts (1 KW)
  4. 1 KWh  (1 unit of electricity)

Answer (Detailed Solution Below)

Option 4 : 1 KWh  (1 unit of electricity)

Electrical and Electronics Measurements Question 12 Detailed Solution

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The correct answer is 1 KWh.

Concept:

Electric bulb: It is an electric device that converts electric energy into heat and light energy.

  • Resistance of the bulb \(R = \frac{{{{\left( {Rated\;voltage} \right)}^2}}}{{\left( {Rated\;power} \right)}}\)
  • If we consider the bulb as a resistor then, we can easily find the current and voltage drops.
  • \(Power\;consumed = {i^2}R\)
  • Power consumed ∝ Brightness

The rate of work done by the electric current is called as electric power.

The difference of potential between two points is called a potential difference.

  • Electric energy (E) = electric power (P) × time (t)

Unit of electric energy = unit of electric power × unit of time = kilowatt × hour = kilowatt-hour

Key Points

  • Given that
    • Power of the bulb = 100 W
    • Time = 10 hours

We know that,

Energy = Power × Time

⇒ Energy consume = 100 w × 10 hrs = 1000 watt - hr = 1 KWh.

For balanced lagging power factor, according to two wattmeter method,

W1 = VL IL cos (30 - ϕ)

W2 = VL IL cos (30 + ϕ)

The total reactive volt-amperes Q is given by

  1. Q = 0
  2. Q = \(\sqrt 3 {V_L}{I_L}\sin \phi\)
  3. Q = 1
  4. Q = VLILsin ϕ

Answer (Detailed Solution Below)

Option 2 : Q = \(\sqrt 3 {V_L}{I_L}\sin \phi\)

Electrical and Electronics Measurements Question 13 Detailed Solution

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In a two-wattmeter method,

The reading of first wattmeter (W1) = VL IL cos (30 – ϕ)

The reading of second wattmeter (W2) = VL IL cos (30 + ϕ)

Total power in the circuit (P) = W1 + W2 = √3 V­­LIL cos ϕ

Total reactive power in the circuit \(Q = √ 3 \left( {{W_1} - {W_2}} \right) =\sqrt3 {V_L}{I_L}\sin \phi\)

Power factor = cos ϕ

\(\phi = {\rm{ta}}{{\rm{n}}^{ - 1}}\left( {\frac{{√ 3 \left( {{W_1} - {W_2}} \right)}}{{{W_1} + {W_2}}}} \right)\)

The braking torque of induction type single-phase energy meter is:

  1. Directly proportional to the square of the flux
  2. Directly proportional to the flux
  3. Inversely proportional to the flux
  4. Inversely proportional to the square of the flux

Answer (Detailed Solution Below)

Option 1 : Directly proportional to the square of the flux

Electrical and Electronics Measurements Question 14 Detailed Solution

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Energy meter:

Energy meter or Watt-hour meter is used to measure the energy in kWh.

It is an integrating type instrument.

Its working principle is similar to the transformer.

There are three essential mechanisms required in the energy meter named Driving torque, Braking torque, and registered mechanism.

Driving torque:

This torque is required to revolve the disc or rotate the disc.

It is obtained by the electromagnetic induction effect.

Braking torque:

It is required to rotate the disc at a constant speed.

It is obtained by using a permanent magnet placed inside the energy meter near the Aluminum disc.

Eddy currents have induced in the magnet due to the movement of the rotating disc through the magnetic field. This eddy current reacts with the flux and exerts a braking torque which opposes the motion of the disk. The speed of the disk can be controlled by changing flux.

Breaking torque of induction type single-phase energy meter is:

\({T_b} = k\frac{{{\phi ^2}}}{{{R_e}}}N \times R\)

K = constant

ϕ = flux

N = speed in rpm

R = radius of the disc

Re = resistance in path of current (i.e. disc)

The braking torque of induction type single-phase energy meter is directly proportional to the square of the flux.

Registered mechanism:

It registers the no. of rotations or revolutions of the disc which is proportional to the energy consumed in kWh.

Meter constant = (No. of revolutions / kWh)

Points to remember:

Creeping:

Sometimes the disc of the energy meter makes the slow but continuous rotation at no load i.e. when the potential coil is excited but with no current flowing in the load called creeping error

This error may be caused due to overcompensation for friction, excessive supply voltage, vibrations, stray magnetic fields, etc

It can be reduced by making two opposite holes on the disc.

Match the following Lissajous figures to their vertical deflection voltage graph.

F31 Shubham B 12-5-2021 Swati D12

  1. 1 - d, 2 - b, 3 - c, 4 - a
  2. 1 - b, 2 - d, 3 - a, 4 - c
  3. 1 - a, 2 - d, 3 - b, 4 - c
  4. 1 - c, 2 - a, 3 - d, 4 - b

Answer (Detailed Solution Below)

Option 4 : 1 - c, 2 - a, 3 - d, 4 - b

Electrical and Electronics Measurements Question 15 Detailed Solution

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Concept-When both pairs of the deflection plates (horizontal deflection plates and vertical deflection plates) of CRO (Cathode Ray Oscilloscope) are connected to two sinusoidal voltages, the patterns appear at CRO screen are called the Lissajous pattern. Shape of these Lissajous pattern changes with changes of phase difference between signal and ration of frequencies applied to the deflection plates (traces) of CRO.

Case – 1: When ø=0 or  ø=360

when the angle is   ø = 0 or   ø = 360, the Lissajous pattern is of the shape of straight line  passing through origin from first quadrant to third quadrant.

F1 Neha B 26.4.21 Pallavi D 1

Case – 2: When, 0 < ø < 90 or 270 < ø <360 : –

when the angle is in the range of 0 < ø < 90 or 270 < ø < 360, the Lissajous pattern is of the shape of Ellipse having major axis passing through origin from first quadrant to third quadrant.

F1 Neha B 26.4.21 Pallavi D 2

Case – 3: When ø=90

when the angle is   ø = 90  the Lissajous pattern is of the shape of circle.

F1 Neha B 26.4.21 Pallavi D 3

Case – 4: When 90  < ø < 180 or 180 < ø < 270

when the angle is in the range of 0 < ø < 90 or 270 < ø < 360, the Lissajous Pattern is of the shape of Ellipse having major axis passing through origin from second quadrant to fourth quadrant.

F1 Neha B 26.4.21 Pallavi D 4

Case – 5: When ø=180

when the angle is   ø = 180  the Lissajous pattern is of the shape of straight line  passing through origin from second  quadrant to  fourth quadrant.

F1 Neha B 26.4.21 Pallavi D 5

Solution:-

Let at horizontal plate voltage graph is

F1 Neha B 26.4.21 Pallavi D 6

Option-1:- It is of case (1) so at vertical plate voltage graph will be with phase difference ϕ = 0 or 360°

F1 Neha B 26.4.21 Pallavi D 7

Option-2:- It is of case (2) so 0 < ϕ < 90° so at vertical plate voltage graph will have phase difference of 0 < ϕ < 90°

F1 Neha B 26.4.21 Pallavi D 8

Option-3:- It is of case (3) so ϕ = 90° ↑ vertical voltage graph of have ϕ = 90° w.r.t horizontal voltage graph

F1 Neha B 26.4.21 Pallavi D 9

Option-4:- It is of case (4) so 90° < ϕ < 180°, vertical voltage graph will have phase difference 90° < ϕ < 180° w.r.t. horizontal voltage graph

F1 Neha B 26.4.21 Pallavi D 10

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