Basic Science and Engineering MCQ Quiz - Objective Question with Answer for Basic Science and Engineering - Download Free PDF
Last updated on Jun 26, 2025
Latest Basic Science and Engineering MCQ Objective Questions
Basic Science and Engineering Question 1:
As per Indian standard Symbolic lines for Engineering drawing, continuous thin lines are used for ________
Answer (Detailed Solution Below)
Basic Science and Engineering Question 1 Detailed Solution
Explanation:
Engineering drawing lines:
- Continuous thin lines: these thin continuous lines could be a straight or curved lines. these lines are used for various representations like projection lines, hatching lines, construction lines, short lines, short center lines, measurement lines, dimension lines, intersection lines, lead lines, backside lines.
Additional Information
Line |
Description |
General Application |
|
A |
|
Continuous thick |
A1 Visible outlines. A2 Visible edges. |
B |
|
Continuous thin (Straight of curved) |
B1 Imaginary lines of intersection. B2 Dimension lines. B3 Projection lines. B4 Leader lines. B5 Hatching lines. B6 Outlines of revolved sections in place. B7 Short centre lines. |
C |
|
Continuous thin free hand |
C1 Limits of partial of interrupted views and sections, if the limit is not a chain thin. |
D |
|
Continuous thin (Straight) with zigzags |
D1 Long break line |
E |
|
Dashed thick |
E1 Hidden outlines. E2 Hidden edges. |
F |
|
Dashed thin |
F1 Hidden outlines. F2 Hidden edges. |
G |
|
Chain thin |
G1 Center lines. G2 Lines of symmetry. G3 Trajectories |
H |
|
Chain thin, thick at ends and changes of direction |
H1 cutting planes. |
J |
|
Chain thick |
J1 Indication of lines or surfaces to which a special requirement applies |
K |
|
Chain thin double dashed |
K1 Outlines of adjacent parts. K2 Alternative or extreme position of movable parts. K3 Centroidal lines. K4 Initial outlines prior to forming K5 Parts situated in front of the cutting plane |
Basic Science and Engineering Question 2:
Identify the convention type for engineering trades in the given engineering drawing.
Answer (Detailed Solution Below)
Basic Science and Engineering Question 2 Detailed Solution
Concept:
In modern engineering, the materials used have become so numerous and diversified that it is not possible to prescribe different hatching lines for different materials.
Following are some conventional representation which is used for the materials:
Type |
Convention |
Material |
Metal |
|
Steel, Iron, Copper, Aluminium, etc. |
|
Lead, Zinc, Tin, White-metal, Etc. |
|
Packing & insulating material |
|
Porcelain, Stoneware, Marble, Slate, etc. |
|
Asbestos, Fiber, Felt, Resin, Paper, Cork, Linoleum, Rubber, Leather, Wax, etc. |
|
Wood |
|
Wood, Plywood, etc. |
Concrete |
|
|
Glass |
|
Glass |
Liquid |
|
Water, Oil, Petrol, Kerosene, etc. |
Basic Science and Engineering Question 3:
Which of the following instruments is a combination of T-Square, set square. protractor and scales, which helps to draw at a faster rate?
Answer (Detailed Solution Below)
Basic Science and Engineering Question 3 Detailed Solution
Explanation:
Mini drafter
- It is an important device used for making drawings quickly & accurately.
- This instrument has a combination of T-square, set-square, protractor, and scales, it helps to draw the drawings at a faster rate.
- They come in different sizes and a pattern called ‘Pantagraph’ type.
- It is fitted on the top left side, edge of the drafting board, mounted on an adjustable frame or table.
Erasing shield:
- When, on a drawing, if a part of a line or some lines among many other lines needs to be erased or modified, in the normal way of erasing will damage the other nearby lines.
- In such a situation an erasing shield is effectively useful.
- It is a thin metallic sheet having small openings of different sizes and shapes.
- A suitable opening is aligned to the line to be erased and the line is removed by the eraser.
Basic Science and Engineering Question 4:
In a lifting machine, an effort of 500 N is to be moved by a distance of 20 m to raise a load of \(10,000 \text{N}\) by a distance of 0.8 m . Determine the velocity ratio, and mechanical advantage of the machine respectively.
Answer (Detailed Solution Below)
Basic Science and Engineering Question 4 Detailed Solution
Explanation:
In lifting machines:
-
Velocity Ratio (VR) = Distance moved by effort / Distance moved by load
-
Mechanical Advantage (MA) = Load lifted / Effort applied
Calculation:
Given:
-
distance moved by effort = 20 m
-
distance moved by load = 0.8 m
-
Load = 10,000 N
-
Effort = 500 N
Velocity Ratio (VR) = 20/0.8 = 25
Mechanical Advantage (MA) = 10000/500 = 20
Basic Science and Engineering Question 5:
What is the dimension of A1 size drawing sheet?
Answer (Detailed Solution Below)
Basic Science and Engineering Question 5 Detailed Solution
Explanation:
Dimensions in "mm" for different sizes of drawing sheets are as follows:
Paper Sizes |
Dimension (mm x mm) |
AO |
841 x 1189 |
A1 |
594 x 841 |
A2 |
420 x 594 |
A3 |
297 x 420 |
A4 |
210 x 297 |
A5 |
148 x 210 |
Top Basic Science and Engineering MCQ Objective Questions
What is Full Form of BIOS?
Answer (Detailed Solution Below)
Basic Science and Engineering Question 6 Detailed Solution
Download Solution PDFThe correct answer is the Basic input/output system.
Important Points
- It is the program a personal computer's microprocessor uses to get the computer system started after you turn it on.
A travels 15 km with a speed of 30 km/h. He travels another 25 km with a speed of 10 km/h. What is his average speed for the entire journey?
Answer (Detailed Solution Below)
Basic Science and Engineering Question 7 Detailed Solution
Download Solution PDFGiven
Distance1 = 15 km, Speed1 = 30 km/h
Distance2 = 25 km, Speed2 = 10 km/h
Formula Used:
Speed = Distance/Time
Average speed = Total distance/Total time
Calculation:
According to the question,
Total distance = 15 + 25 = 40 km
Total time = 15/30 + 25/10
⇒ (15 + 75)/30 = 90/30 = 3 hours
Average speed = 40/3 km/h
∴ The average speed for the entire journey is 40/3 km/h.
Given
D1 = 15 km, S1 = 30 km/h
D2 = 25 km, S2 = 10 km/h
Formula Used:
Average speed = \(\frac{{{D_1} + {D_2}}}{{\frac{{{D_1}}}{{{S_1}}} + \frac{{{D_2}}}{{{S_2}}}}}\)
Calculation:
Average speed for the entire journey = \(\frac{{15 + 25}}{{\frac{{15}}{{30}} + \frac{{25}}{{10}}}}\)
\(= \frac{{40}}{{0.5 + 2.5}}\)
\(= \frac{{40}}{3}\;km/h\)In a Class 3 lever, the effort and load move:
Answer (Detailed Solution Below)
Basic Science and Engineering Question 8 Detailed Solution
Download Solution PDFExplanation:
- A lever is a simple machine consisting of a beam or rigid rod pivoted at a fixed hinge, or fulcrum, used to transfer a force to a load and usually to provide a mechanical advantage.
- On the basis of the locations of fulcrum, load, and effort, the lever is divided into three types.
- First Class Lever:In a first-class lever, the fulcrum is located between the effort and the load. When force is applied to one end of the lever (effort arm), it causes the other end to move, exerting force on the load. Examples include seesaws, crowbars, and scissors.
- Second-class lever: In a second-class lever, the load is located between the fulcrum and the effort. This means that the effort arm is always longer than the load arm. When force is applied to the effort arm, it causes the load to move. Examples include wheelbarrows, bottle openers, and nutcrackers.
- Third-class lever: In a third-class lever, the effort is applied between the fulcrum and the load. This means that the load arm is always longer than the effort arm. While third-class levers don't provide a mechanical advantage like first and second-class levers, they allow for greater speed and range of motion. Examples include fishing rods, shovels, and tweezers.
Lux is unit of which physical quantity?
Answer (Detailed Solution Below)
Basic Science and Engineering Question 9 Detailed Solution
Download Solution PDFThe derived SI unit of illuminance is the lux (lx).
Quantity |
Unit |
Luminous energy |
lumen second (lm.s) |
Luminous flux/luminous power |
lumen (lm) |
Luminous intensity |
candela (cd) |
Luminance |
candela per square metre (cd/m2) |
Illuminance |
lux (lx) |
Luminous emittance |
lux (lx) |
Luminous exposure |
lux second (lx.s) |
_________ is made up of smoke and fog.
Answer (Detailed Solution Below)
Basic Science and Engineering Question 10 Detailed Solution
Download Solution PDF- It is a type of air pollutant.
- It is derived from vehicular emission from internal combustion engines and industrial fumes that react in the atmosphere with sunlight to form secondary pollutants.
- In certain cities, such as Delhi, smog severity is often increased by stubble burning in neighboring agricultural areas.
- It is highly toxic to humans and can cause severe sickness, shortened life or death.
A simple machine will be self-locking, if its efficiency is:
Answer (Detailed Solution Below)
Basic Science and Engineering Question 11 Detailed Solution
Download Solution PDFExplanation:
If the removal of effort while lifting, results in lowering of the load, the machine is said to be reversible.
The machine is said to be self-locking if the load is not lowered on the removal of the effort.
Important Points
A lifting machine is reversible if its efficiency is greater than 50 per cent and self-locking if its efficiency is less than 50 per cent.
The SI unit of heat is
Answer (Detailed Solution Below)
Basic Science and Engineering Question 12 Detailed Solution
Download Solution PDFThe correct answer is joule.
- The unit of heat in the SI system is Joule.
- A unit of energy equal to the work done when a force of one newton acts through a distance of one meter.
Important Points
- The other common units for heat are-
- BTU (Btu) - British Thermal Unit - also known as a "heat unit" in the United States.
- Calorie: The amount of heat required to raise the temperature of one gram of water 1oC.
- Erg is a unit of energy.
- It equal to the force of one dyne over a distance of one centimeter.
- 1 erg = 10-7 joule.
- Watt is a unit (SI) of power.
- It is equal to one joule of work performed per second.
- 1 horsepower = 746 watt
Key Points
- 1 joule = 0.14 calorie = 9.478 x 10-4 Btu.
- 4.184 joule of heat energy (or one calorie) is required to raise the temperature of a unit weight (1 g) of water from 0oC to 1oC, or from 32oF to 33.8oF.
- 1 dyne = 0.00001 newton.
When using an isometric view, you line up the drawing along three axis that are separated by _________ from each other.
Answer (Detailed Solution Below)
Basic Science and Engineering Question 13 Detailed Solution
Download Solution PDFThe correct answer is 120-degree.
Key Points
- Draw horizontal and vertical lines to represent an isometric object.
- While horizontal lines are drawn at a 30-degree angle to the horizontal plane, vertical lines remain vertical.
- All three axes must be at a 120-degree angle from one another. Now, if you adhere to rule number 1, this is accomplished automatically.
- An object's three faces are all equally foreshortened in the isometric projection.
- Any mechanical drawing or system is typically explained with an isometric drawing.
- It can be found on instructions for model kits like Lego, Gundam, and others, as well as mechanical infographics.
A bearing or other device is needed to hold the beam in ________ lever/levers.
Answer (Detailed Solution Below)
Basic Science and Engineering Question 14 Detailed Solution
Download Solution PDFKey Points
- In Class 1 and Class 3 levers, the fulcrum or the force is located at one end, requiring support like a bearing or pivot to hold the beam in place.
- Class 1 lever has the fulcrum between the effort and the load (e.g., seesaw), which must be held with a pivot/bearing.
- Class 3 lever has the effort between the fulcrum and the load (e.g., tweezers), also requiring support to stabilize the beam.
- These types of levers need a fixed point or axis of rotation, which is typically provided by a bearing, hinge, or other support.
- Class 2 levers do not usually require a bearing to stabilize the beam in the same way, as the load lies between the effort and fulcrum (e.g., wheelbarrow).
Additional Information
- Class 1 Lever:
- Fulcrum between load and effort.
- Examples: Seesaw, scissors, crowbar.
- Can multiply force or speed depending on fulcrum position.
- Class 2 Lever:
- Load between effort and fulcrum.
- Examples: Wheelbarrow, nutcracker.
- Always multiplies force; mechanical advantage > 1.
- Class 3 Lever:
- Effort between fulcrum and load.
- Examples: Tweezers, tongs, human forearm.
- Multiplies speed and distance; mechanical advantage < 1.
- Role of Bearings:
- Bearings provide rotational support to the lever beam, minimizing friction.
- Essential in systems where a stable pivot point is necessary.
- Mechanical Advantage:
- Levers provide mechanical advantage by trading force for distance or vice versa.
What is the effect of greenhouse gases on the average temperature of the earth’s atmosphere?
Answer (Detailed Solution Below)
Basic Science and Engineering Question 15 Detailed Solution
Download Solution PDF- The greenhouse effect occurs when Earth's atmosphere traps solar radiation because of the presence of certain gases called green house gases.
- This results in an overall increase in the average temperature of the earth’s atmosphere.
- Some major greenhouse gases are- Carbon dioxide, Methane, Nitrous oxide, Chlorofluorocarbons, etc.