Question
Download Solution PDFसमांतरभुज चौकोनाचा पाया त्याच्या उंचीच्या दुप्पट आहे. क्षेत्रफळ 392 चौ.मी असल्यास, त्याची उंची किती आहे?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिलेले आहे:
समांतरभुज चौकोनाचा पाया त्याच्या उंचीच्या दुप्पट आहे.
क्षेत्रफळ = 392 चौ.मी
वापरलेली संकल्पना:
क्षेत्रफळ = b × h
जेथे "b" हा पाया आहे आणि "h" समांतरभुज चौकोनाची उंची आहे.
गणना:
समांतरभुज चौकोनाची उंची x असू द्या,
म्हणून, त्याचा आधार = 2x
प्रश्नानुसार,
x × 2x = 392
⇒ 2x2 = 392
⇒ x2 = 196
⇒ x = 14 मीटर
म्हणून, उंची = 14 मीटर
∴ उंची 14 मीटर आहे.
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