Question
Download Solution PDFजर एका अपूर्णांकाचा अंश 20% ने वाढविला आणि छेद 30% ने कमी केला, तर मिळणारा अपूर्णांक \(\frac{{39}}{{25}}\) आहे. तर मूळ अपूर्णांक किती?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिलेल्याप्रमाणे:
जर एका अपूर्णांकाचा अंश 20% ने वाढविला आणि छेद 30% ने कमी केला, तर मिळणारा अपूर्णांक 39/25 आहे.
वापरलेली संकल्पना:
टक्केवारी
गणना:
अपूर्णांक x/y आहे असे मानू
प्रश्नानुसार,
⇒ \(\frac{{x + \frac{{20x}}{{100}}}}{{y - \frac{{30y}}{{100}}}} = \frac{{39}}{{25}}\)
⇒ \(\frac{{\frac{{6x}}{5}}}{{\frac{{7y}}{{10}}}} = \frac{{39}}{{25}}\)
⇒ \(\frac{{6x}}{{7y}} = \frac{{39}}{{25}} \times \frac{5}{{10}}\)
⇒ \(\frac{x}{y} = \frac{{39}}{{50}} \times \frac{7}{6}\)
⇒ \(\frac{x}{y} = \frac{{273}}{{300}}\)
∴ \(\frac{x}{y} = \frac{{91}}{{100}}\)
Last updated on Jul 21, 2025
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