जर a + b + c = 14, ab + bc + ca = 47 आणि abc = 15,  तर  a3 + b3 +c3 = ?

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NTPC CBT-I (Held On: 4 Jan 2021 Shift 2)
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  1. 815
  2. 825
  3. 835
  4. 845

Answer (Detailed Solution Below)

Option 1 : 815
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RRB NTPC CBT-I Official Paper (Held On: 4 Jan 2021 Shift 1)
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Detailed Solution

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दिलेले आहे:

a + b + c = 14, ab + bc + ca = 47 आणि abc = 15

वापरलेली संकल्पना:

a³ + b³ + c³ - 3abc = (a + b + c) × [(a + b + c)² -3(ab + bc + ca)]

गणना:

a³ + b³ + c³ - 3abc = 14 × [(14)² - 3 × 47]

⇒ a³ + b³ + c³ – 3 × 15 = 14(196 – 141)

⇒ a³ + b³ + c³ = 14(55) + 45

⇒ 770 + 45

⇒ 815

∴ योग्य उत्तर पर्याय 1 आहे.

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