Question
Download Solution PDFदिलेल्या संख्यांच्या व्यस्त संख्यांच्या बेरजेचा व्यस्त शोधा.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिलेले आहे:
वापरलेले सूत्र:
दिलेल्या संख्यांच्या व्यस्त संख्यांच्या बेरजेचा व्यस्त:
गणना:
व्यस्त संख्या: 5/2, 4/5, 8/6, 5/6, 6/9
व्यस्त संख्यांची बेरीज = 5/2 + 4/5 + 8/6 + 5/6 + 6/9
⇒ बेरीज = 5/2 + 4/5 + 4/3 + 5/6 + 2/3
⇒ बेरीज = 75/30 + 24/30 + 40/30 + 25/30 + 20/30
⇒ बेरीज = (75 + 24 + 40 + 25 + 20)/30
⇒ बेरीज = 184/30 = 92/15
अशाप्रकारे, बेरजेचा व्यस्त = 1/(92/15) = 15/92
∴ पर्याय (2) योग्य आहे.
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