Question
Download Solution PDFसमीकरण 7x2 - 6x + 1 = 0 के मूल tan α और tan β हैं, जहाँ 2α और 2β एक त्रिभुज के कोण हैं। निम्नलिखित में से कौन सा सही है?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFव्याख्या:
दिया गया है:
tanα और tanβ, 7x2 - 6x + 1 = 0 के मूल हैं
इसलिए,
⇒ tanα + tanβ = 6/7...(1)
⇒ tanα.tanβ = 1/7...(2)
⇒ tan(α+β) =
⇒ α +β = 45°
⇒ 2α +2β = 90°
इसका अर्थ है कि त्रिभुज का तीसरा कोण 90° है।
इसलिए, त्रिभुज समकोण है।
चूँकि
⇒tanα - tanβ =
साथ ही
⇒ tan(α -β) =
⇒ tan2(α -β) =
=
इस प्रकार 2α≠2β
∴ विकल्प (c) सही है।
Last updated on May 30, 2025
->UPSC has released UPSC NDA 2 Notification on 28th May 2025 announcing the NDA 2 vacancies.
-> A total of 406 vacancies have been announced for NDA 2 Exam 2025.
->The NDA exam date 2025 has been announced for cycle 2. The written examination will be held on 14th September 2025.
-> Earlier, the UPSC NDA 1 Exam Result has been released on the official website.
-> The selection process for the NDA exam includes a Written Exam and SSB Interview.
-> Candidates who get successful selection under UPSC NDA will get a salary range between Rs. 15,600 to Rs. 39,100.
-> Candidates must go through the NDA previous year question paper. Attempting the NDA mock test is also essential.