एक शंक्वाकार तंबू के आधार की त्रिज्या 9 m है और इसकी ऊँचाई 12 m है, यदि इसका मूल्य ₹100 प्रति π m2 है, तो इसे बनाने के लिए आवश्यक सामग्री का मूल्य ज्ञात कीजिए।

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RRB NTPC CBT 2 Level -6 Official paper (Held On: 9 May 2022 Shift 1)
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  1. ₹14,500
  2. ₹13,000
  3. ₹15,000
  4. ₹13,500

Answer (Detailed Solution Below)

Option 4 : ₹13,500
Free
RRB NTPC CBT-I Official Paper (Held On: 4 Jan 2021 Shift 1)
100 Qs. 100 Marks 90 Mins

Detailed Solution

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दिया गया है:

एक शंक्वाकार तम्बू के आधार की त्रिज्या 9 मीटर है और इसकी ऊँचाई 12 मीटर है।

प्रयुक्त अवधारणा:

शंकु का वक्र पृष्ठीय क्षेत्रफल = π × त्रिज्या × तिर्यक ऊँचाई

तिर्यक ऊँचाई

गणना:

शंक्वाकार तम्बू की तिर्यक ऊँचाई = 15 सेमी

अत:, शंक्वाकार तंबू का वक्र पृष्ठीय क्षेत्रफल = π × 9 × 15 = 135π मीटर2

इस प्रकार, सामग्री का मूल्य = (135π × 100) ÷ π = 13,500 रुपये

सामग्री का मूल्य 13,500 रुपये है।

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