Question
Download Solution PDFO केंद्र वाले एक वृत्त में, इसके बिंदु Q पर स्पर्श रेखा PQR है। AB वृत्त के अन्दर जीवा है जो स्पर्श रेखा के इस प्रकार समांतर है कि ∠BQR = 70° है। ∠AQB की माप क्या है?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDF⇒ ∠BQR = 70° (दिया है)
⇒ ∠BQR = ∠QBA = 70° (एकांतर अन्तः कोण)
⇒ ∠BQR = ∠QAB = 70° (एकांतर खंड प्रमेय)
ΔAQB में
⇒ ∠AQB + ∠QAB + ∠QBA = 180°
⇒ ∠AQB + 70° + 70° = 180°
⇒ ∠AQB = 180° – 140° = 40°
Last updated on Jul 15, 2025
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