Question
Download Solution PDFIn a circle with centre O, PQR is a tangent at the point Q on it. AB is a chord in the circle parallel to the tangent such that ∠BQR = 70°. What is the measure of ∠AQB?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDF⇒ ∠BQR = 70° (Given)
⇒ ∠BQR = ∠QBA = 70° (Alternate interior angle)
⇒ ∠BQR = ∠QAB = 70° (Alternate segment theorem)
In ΔAQB
⇒ ∠AQB + ∠QAB + ∠QBA = 180°
⇒ ∠AQB + 70° + 70° = 180°
⇒ ∠AQB = 180° – 140° = 40°
Last updated on Jul 19, 2025
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