Question
Download Solution PDFO কেন্দ্রবিশিষ্ট একটি বৃত্তে, PQR হল তার উপর Q বিন্দুতে একটি স্পর্শক। AB হল স্পর্শকের সমান্তরাল বৃত্তের একটি জ্যা যেখানে ∠BQR = 70°, ∠AQB এর পরিমাপ কি?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDF⇒ ∠BQR = 70° (প্রদত্ত)
⇒ ∠BQR = ∠QBA = 70° (বিকল্প অভ্যন্তরীণ কোণ)
⇒ ∠BQR = ∠QAB = 70° (বিকল্প রেখাংশ উপপাদ্য)
ΔAQB-তে
⇒ ∠AQB + ∠QAB + ∠QBA = 180°
⇒ ∠AQB + 70° + 70° = 180°
⇒ ∠AQB = 180° - 140° = 40°
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