Answer (Detailed Solution Below)

Option 1 :
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UP TGT Hindi FT 1
125 Qs. 500 Marks 120 Mins

Detailed Solution

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संकल्पना:

दो सदिश के पार/सदिश गुणनफल को इस प्रकार परिभाषित किया गया है:

जहाँ θ बीच का कोण है

जहाँ  इकाई सदिश है। 

यदि  और , तो उनके अन्योन्य गुणनफल है:

गणना:

Let,

= î(4 + 0) - ĵ (3 - 0) + k̂(- 3 - 4)

⇒ 

Now,

 

⇒ 

Therefore, 

 

 

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