Question
Download Solution PDFएक स्पर गियर में मॉड्यूल 2 mm और 30 दांतों की संख्या 200 rpm पर घूमती है। तो mm में इसकी वृत्तीय पिच क्या होगी?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFअवधारणा:
पिच लाइन वेग,
VP \(= {\rm{\omega }}.r = \frac{{2π N}}{{60}} × \frac{d}{2}\)
\(V_P= \frac{{2π N}}{{60}} × \frac{{mT}}{2}\;\;\;\;\;\;\;\left( {as\;m = \frac{d}{T}} \right)\)
वृत्तीय पिच,
p = π m
गणना:
दिया गया है:
दांतों की संख्या (T) = 30
मॉड्यूल (m) = 2 mm
चाल (N) = 200 rpm
p = π × 2
p = 6.28 mm
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