Question
Download Solution PDFFind the rank of the matrix \(\left(\begin{matrix} 8 & 1 & 3 & 6 \\\ 0 & 3 & 2 & 2 \\\ -8 & -1 & -3 & -4 \end{matrix}\right)\)
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
Rank:
The rank of a matrix is a number equal to the order of the highest order non-vanishing minor, that can be formed from the matrix.
For matrix A, it is denoted by ρ(A).
The rank of a matrix is said to be r if,
- There is at least one non-zero minor of order r.
- Every minor of matrix A having order higher than r is zero.
Echelon form: A matrix is said to be in echelon form if
- Leading non-zero elements in each row is behind leading non-zero elements in the previous row.
- All the zero rows are below all the non-zero rows.
Steps to find the echelon form and rank of a matrix:
- To reduce the matrix to the echelon form we can apply the Gauss elimination method on the matrix and can convert the matrix to an upper triangular matrix (lower off-diagonal elements zero).
- Then we can count the number of non -zero rows in this upper triangular matrix to get the rank of the matrix.
Calculation:
Let
\(A = \left(\begin{matrix} 8 & 1 & 3 & 6 \\\ 0 & 3 & 2 & 2 \\\ -8 & -1 & -3 & -4 \end{matrix}\right)\)
by \(C_1 \rightarrow \frac{1}{8}C_1\)
\(A\ =\ \left(\begin{matrix} 1 & 1 & 3 & 6 \\\ 0 & 3 & 2 & 2 \\\ -1 & -1 & -3 & -4 \end{matrix}\right)\)
by \(R_3 \rightarrow R_3 + R_1\)
\(\Rightarrow \ A\ =\ \left(\begin{matrix} 1 & 1 & 3 & 6 \\\ 0 & 3 & 2 & 2 \\\ 0 & 0 & 0 & 2 \end{matrix}\right)\)
The last equivalent matrix is in the echelon form. The number of non-zero rows in this matrix is 3. Therefore it's ranked in 3.
Hence rank A = 3.
Important Points
Other properties of rank of a matrix are:
- The rank of a matrix does not change by elementary transformation, we can calculate the rank by changing the matrix into Echelon form. In the Echelon form, the rank of a matrix is the number of non-zero rows of the matrix.
- The rank of a matrix is zero if the matrix is null.
- ρ(A) ≤ min (Row, Column)
- ρ(AB) ≤ min [ρ(A), ρ(B)]
- ρ(AT A) = ρ(A AT) = ρ(A) = ρ(AT)
- If A and B are matrices of the same order, then ρ(A + B) ≤ ρ(A) + ρ(B) and ρ(A - B) ≥ ρ(A) - ρ(B).
- If Aθ is the conjugate transpose of A, then ρ(Aθ) = ρ(A) and ρ(A Aθ) = ρ(A).
- The rank of a skew-symmetric matrix cannot be one.
Last updated on Jul 4, 2025
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