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Maths MCQ Quiz in தமிழ் - Objective Question with Answer for Maths - இலவச PDF ஐப் பதிவிறக்கவும்

Last updated on Mar 15, 2025

பெறு Maths பதில்கள் மற்றும் விரிவான தீர்வுகளுடன் கூடிய பல தேர்வு கேள்விகள் (MCQ வினாடிவினா). இவற்றை இலவசமாகப் பதிவிறக்கவும் Maths MCQ வினாடி வினா Pdf மற்றும் வங்கி, SSC, ரயில்வே, UPSC, மாநில PSC போன்ற உங்களின் வரவிருக்கும் தேர்வுகளுக்குத் தயாராகுங்கள்.

Latest Maths MCQ Objective Questions

Top Maths MCQ Objective Questions

Maths Question 1:

In triangles \(ABC\) and \(DEF\), the corresponding angles are equal. If the side \(AB\) is \(15\) units and the corresponding side \(DE\) is \(20\) units, what is the ratio of the area of triangle \(ABC\) to the area of triangle \(DEF\)?

  1. \(27:64\)
  2. \(9:16\)
  3. \(4:5\)
  4. \(3:4\)

Answer (Detailed Solution Below)

Option 2 : \(9:16\)

Maths Question 1 Detailed Solution

The ratio of the areas of similar triangles is the square of the ratio of their corresponding sides. Here, the ratio of \(AB\) to \(DE\) is \(\frac{15}{20} = \frac{3}{4}\). Thus, the ratio of the areas is \(\left(\frac{3}{4}\right)^2 = \frac{9}{16}\). Therefore, the ratio of the area of triangle \(ABC\) to the area of triangle \(DEF\) is \(9:16\).

Maths Question 2:

A flagpole casts a shadow of 12 feet. At the same time, a nearby tree that is 8 feet tall casts a shadow of 6 feet. How tall is the flagpole?

  1. 10 feet
  2. 14 feet
  3. 16 feet
  4. 18 feet

Answer (Detailed Solution Below)

Option 3 : 16 feet

Maths Question 2 Detailed Solution

To find the height of the flagpole, we can use the concept of similar triangles. The tree and its shadow form one triangle, and the flagpole and its shadow form another triangle. Since the sun's rays are parallel, these triangles are similar. Therefore, the ratio of the height to the shadow length is the same for both. For the tree, the ratio is \(\frac{8}{6}\). For the flagpole, let's call its height \(h\), giving us the ratio \(\frac{h}{12}\). Setting these equal gives us the equation: \(\frac{8}{6} = \frac{h}{12}\). Solving for \(h\) involves cross-multiplying to get: \(8 \times 12 = 6h\). Simplifying: \(96 = 6h\). Dividing both sides by 6 yields \(h = 16\) feet. Thus, the flagpole is 16 feet tall. Option 3 is correct.

Maths Question 3:

The cosine of angle C in a right triangle is \( \frac{5}{13} \). Find the sine of the angle that complements C.

  1. \( \frac{5}{13} \)
  2. \( \frac{12}{13} \)
  3. \( \frac{13}{5} \)
  4. \( \frac{1}{2} \)

Answer (Detailed Solution Below)

Option 1 : \( \frac{5}{13} \)

Maths Question 3 Detailed Solution

The sine of an angle is equal to the cosine of its complementary angle. Therefore, \( \sin(90^\circ - C) = \cos(C) = \frac{5}{13} \). So, the sine of the angle complementary to C is \( \frac{5}{13} \), making option 1 correct. Option 2 is the sine of angle C itself, not its complement. Options 3 and 4 are incorrect as they do not correspond to the given trigonometric ratios.

Maths Question 4:

A factory produces 400 gadgets, and 92% of them pass quality inspection. How many gadgets pass inspection?

  1. 360
  2. 368
  3. 370
  4. 368

Answer (Detailed Solution Below)

Option 4 : 368

Maths Question 4 Detailed Solution

To find out how many gadgets pass inspection, calculate 92% of 400. Convert the percentage to a decimal: \(92\% = 0.92\). Then, multiply 400 by 0.92: \(400 \times 0.92 = 368\). Thus, 368 gadgets pass inspection. Option 4 is correct, while options 1, 2, and 3 do not represent 92% of 400.

Maths Question 5:

What is the median of the following data set: 5, 11, 15, 18, 22?

  1. 11
  2. 13
  3. 15
  4. 18

Answer (Detailed Solution Below)

Option 3 : 15

Maths Question 5 Detailed Solution

To find the median, we need to arrange the data in ascending order (which it already is) and find the middle value. Since there are 5 numbers, the median is the third number in the sorted list. Thus, the median is 15. Option 1 is incorrect as 11 is the first quartile, not the median. Option 2 is incorrect as 13 does not appear in the data set. Option 4 is incorrect as 18 is the fourth value, not the middle one. Therefore, the correct answer is 15.

Maths Question 6:

In a study, two groups of athletes were tested for their maximum oxygen uptake levels. The data for each group is summarized in the table below.

| Group | Sample Size | Mean (ml/kg/min) | Standard Deviation (ml/kg/min) |

|-------|-------------|------------------|---------------------------------|

| C | 1,800 | 50 | 8.5 |

| D | 1,800 | 50 | 12.3 |

Which of the following statements is true based on the table?

  1. The Group C data set was identical to the Group D data set.
  2. Group D had more consistent oxygen uptake levels than Group C.
  3. The spread of oxygen uptake levels was greater in Group D than in Group C.
  4. The median oxygen uptake level of Group D is higher than that of Group C.

Answer (Detailed Solution Below)

Option 3 : The spread of oxygen uptake levels was greater in Group D than in Group C.

Maths Question 6 Detailed Solution

The correct answer is option 3. The standard deviation is a measure of the spread of data points around the mean. A larger standard deviation indicates that the data points are more spread out. Here, Group D has a standard deviation of 12.3 ml/kg/min, which is larger than the standard deviation of Group C, which is 8.5 ml/kg/min. This means that the oxygen uptake levels in Group D have a larger spread compared to Group C.

Option 1 is incorrect because identical data sets would have identical means and standard deviations, which is not the case here.

Option 2 is incorrect because a larger standard deviation in Group D indicates less consistency, not more.

Option 4 is incorrect because the problem does not provide information about medians, and the means are identical, so we cannot infer anything about the medians.

Maths Question 7:

A list of 60 numbers has a mean of 25 and a median of 30. If all numbers above the median are tripled and all numbers below the median are halved, which statistical measure is altered?

  1. Median
  2. Mean
  3. Total sum
  4. Standard deviation

Answer (Detailed Solution Below)

Option 4 : Standard deviation

Maths Question 7 Detailed Solution

Tripling all numbers above the median and halving all numbers below the median results in a significant change in the spread of the data. The median remains unchanged as it is the central value of the ordered list. The mean, which depends on the total sum, will change due to the drastic modifications in individual values. The total sum changes as the transformations alter the overall sum of the data. The standard deviation, which measures the spread of the data points from the mean, will definitely increase due to the increased variability in the data. Thus, the standard deviation is altered.

Maths Question 8:

The ratio \(\frac{c}{d} = 6\) and \(\frac{72c}{kd} = 6\). Find \(k\).

  1. 12
  2. 6
  3. 72
  4. 36

Answer (Detailed Solution Below)

Option 3 : 72

Maths Question 8 Detailed Solution

The ratio \(\frac{c}{d} = 6\) implies \(c = 6d\). Substituting into the equation \(\frac{72c}{kd} = 6\), we have \(\frac{72(6d)}{kd} = 6\). Simplifying gives \(\frac{432d}{kd} = 6\). Canceling \(d\) results in \(\frac{432}{k} = 6\). Solving for \(k\), multiply both sides by \(k\) to get \(432 = 6k\). Dividing both sides by 6, \(k = 72\). Therefore, \(k\) is 72.

Maths Question 9:

For the function \( j(x) = x^2 + 6x + 9 \), find the value of \( x \) when \( j(x) = 0 \).

  1. 3
  2. -3
  3. 0
  4. -9

Answer (Detailed Solution Below)

Option 2 : -3

Maths Question 9 Detailed Solution

The given function is \( j(x) = x^2 + 6x + 9 \). We set \( j(x) = 0 \), resulting in \( x^2 + 6x + 9 = 0 \). This can be factored as \( (x + 3)^2 = 0 \), giving \( x = -3 \). Therefore, the correct option is -3, which is option 2. This shows that the quadratic has a repeated root at \( x = -3 \).

Maths Question 10:

A scientist observes that a certain chemical reaction doubles in concentration every 2 hours. If the initial concentration is \(0.5\) moles per liter, what is the concentration after 8 hours?

  1. 1 moles per liter
  2. 2 moles per liter
  3. 4 moles per liter
  4. 8 moles per liter

Answer (Detailed Solution Below)

Option 4 : 8 moles per liter

Maths Question 10 Detailed Solution

The concentration doubles every 2 hours. After 8 hours, the concentration will have doubled \(\frac{8}{2} = 4\) times. The concentration is given by the formula \(C = 0.5 \times 2^n\), where \(n\) is the number of doubling periods. Substituting \(n = 4\), we have \(C = 0.5 \times 2^4 = 0.5 \times 16 = 8\) moles per liter. Therefore, the concentration after 8 hours is 8 moles per liter. Option 1 is incorrect because it represents the concentration after 2 hours. Option 2 is incorrect because it represents the concentration after 4 hours. Option 3 is incorrect because it represents the concentration after 6 hours.

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