Question
Download Solution PDFThe voltage applied to the gate terminal of a thyristor is a rectangular pulse of 12 V with a period of 50 us and a duty cycle of 0.2. What is the average power loss in the gate circuit, if the peak gate power loss is 5 W?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept
The average power loss in the gate circuit of a thyristor is calculated using the formula:
Pavg = Ppeak × Duty Cycle
Calculation
Given, Ppeak = 5 W
Duty Cycle = 0.2
Pavg = 5 × 0.2
Pavg = 1 W
Last updated on Jul 18, 2025
-> MPPGCL Junior Engineer Notification 2025 has been released for various fields of post (Advt No. 3233).
-> MPPGCL has announced a total of 90 vacancies for Civil, Mechanical, Electrical, and Electronics Engineering (Junior Engineer).
-> Interested candidates can submit their online application form, from 23rd July to 21st August 2025.
-> MPPGCL Junior Engineer result PDF has been released at the offiical website.
-> The MPPGCL Junior Engineer Exam Date has been announced.
-> The MPPGCL Junior Engineer Notification was released for 284 vacancies.
-> The selection process includes a Computer Based Test and Document Verification.
-> Candidates can check the MPPGCL JE Previous Year Papers which helps to understand the difficulty level of the exam.