Question
Download Solution PDFThe nature of the response shown below is:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept
A second-order transfer function is represented as:
\({C(s)\over R(s)}={ω_n^2\over s^2+2ζω_ns+ω_n^2}\)
where, ωn = Natural frequency
ζ = Damping ratio
The nature of damping with respect to the damping ratio is:
|
Damping ratio |
Damping |
|
ζ = 0 |
Undamped |
|
0 < ζ < 1 |
Underdamped |
|
ζ = 1 |
Critically damped |
|
ζ > 1 |
Overdamped |
Calculation
Given, \({C(s)\over R(s)}={20\over s^2+8s+20}\)
\(ω_n^2=20\)
ωn =4.472 rad/s
2ζωn = 8
\(\zeta={8\over 2\times 4.472}\)
ζ = 0.894
Hence, the system is underdamped.
Last updated on Jul 18, 2025
-> MPPGCL Junior Engineer Notification 2025 has been released for various fields of post (Advt No. 3233).
-> MPPGCL has announced a total of 90 vacancies for Civil, Mechanical, Electrical, and Electronics Engineering (Junior Engineer).
-> Interested candidates can submit their online application form, from 23rd July to 21st August 2025.
-> MPPGCL Junior Engineer result PDF has been released at the offiical website.
-> The MPPGCL Junior Engineer Exam Date has been announced.
-> The MPPGCL Junior Engineer Notification was released for 284 vacancies.
-> The selection process includes a Computer Based Test and Document Verification.
-> Candidates can check the MPPGCL JE Previous Year Papers which helps to understand the difficulty level of the exam.