Question
Download Solution PDFf(x) = xn, n ≠ 0 అనే ఫంక్షన్ అన్నిxకి భేదమైనది అనుకుందాం. అప్పుడు n విరామం యొక్క ఏదైనా మూలకం కావచ్చు
- [1, ∞)
- (0, ∞)
- None of the above
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFలెక్కింపు:
ఇచ్చినది: f(x) = xn, n ≠ 0.
F’(x) = nxn – 1
x యొక్క అన్నీ విలువలకుf(x) బేధం కావాలంటే,n – 1 ≥ 0
కాబట్టి, n ≥ 1.
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