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What is the minimum value of the function f(x) = log10(x2 + 2x + 11)? 

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NDA-II 2024 (Maths) Official Paper (Held On: 01 Sept, 2024)
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Answer (Detailed Solution Below)

Option 2 : 1
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Detailed Solution

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Explanation:

f(x) = log10 (x2 + 2x + 11) for minimum f'(x) = 0

⇒ \(\frac{2x + 2 }{x^2+2x+11} = 0\) .. (Since x2 +2x + 11 > 0)

At x = –1, we get minumum value of f(x).

⇒ f(–1) = log1010 = 1

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