Question
Download Solution PDF10.5 सेमी उंचीच्या समच्छिन्न शंकुच्या दोन गोलाकार बाजूंची त्रिज्या अनुक्रमे 5 सेमी आणि 3 सेमी आहेत. (π = 22/7) सेमी3मध्ये त्याचे घनफळ किती आहे?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFसमच्छिन्न शंकुच्या दोन गोलाकार चेहऱ्यांची त्रिज्या 5 सेमी आणि 3 सेमी आहेत
शंकूच्या गोलाकारसमच्छिन्न शंकुची उंची H = 10.5 सेमी
जस आपल्याला माहित आहे,
समच्छिन्न शंकुचे घनफळ = 1/3 × π [R 2 + r 2 + Rr] H
⇒ 1/3 × 22/7 × [52 + 32 + 5 × 3] × 10.5
⇒ 11 × [25 + 9 + 15]
⇒ 11 × 49
⇒ 539Last updated on Jul 19, 2025
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