Question
Download Solution PDFलंब वर्तुळाकार वृत्तचितीचा व्यास 14 सेमी आणि उंची 2 सेमी आहे. त्याच्या वक्रपृष्ठा चे क्षेत्रफळ आणि एकूण पृष्ठभागाची बेरीज किती आहे: (π = \(\frac{22}{7}\) चा वापर करा )
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिलेल्याप्रमाणे:
वृत्तचितीचा व्यास = 14 सेमी
वृत्तचितीची उंची = 2 सेमी
π = २२/७
वापरलेले सूत्र:
वृत्तचितीचे वक्रपृष्ठचे क्षेत्रफळ = 2πrh
वृत्तचितीचे एकूण पृष्ठभाग क्षेत्रफळ = 2πr(r + h)
स्पष्टीकरण:
वक्र पृष्ठभागाचे क्षेत्रफळ = 2πrh
= 2 × 22/7 × 7 × 2
= 44 × 2
= 88 सेमी²
एकूण पृष्ठभागाचे क्षेत्रफळ = 2πr(r + h)
= 2 × 22/7 × 7(7 + 2)
= 44 × 9
= 396 सेमी²
पृष्ठभागाच्या क्षेत्रफळांची बेरीज = 88 cm² + 396 cm²
= 484 सेमी²
∴ योग्य उत्तर पर्याय 1 हे आहे.
Last updated on Jun 30, 2025
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