दिलेली पदावलीला सरळ रुप द्या.

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SSC Selection Post 2024 (Higher Secondary Level) Official Paper (Held On: 25 Jun, 2024 Shift 2)
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  1. 12
  2. 9
  3. 10
  4. 14

Answer (Detailed Solution Below)

Option 2 : 9
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SSC Selection Post Phase 13 Matriculation Level (Easy to Moderate) Full Test - 01
100 Qs. 200 Marks 60 Mins

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दिलेल्याप्रमाणे:

पदावली सरळ रुप द्या:

वापरलेले सूत्र:

पदावली तीन चलांचा समावेश असलेल्या निर्धारकाची ओळख दर्शवते:

(a3 + b3 + c3 - 3abc) / (a2 + b2 + c2 - ab - bc - ca) = a + b + c

गणना:

समजा a = 1.5, b = 2.7, आणि c = 4.8.

सूत्र वापरुयात:

अंश = 1.53 + 2.73 + 4.83 - 3(1.5)(2.7)(4.8)

भाजक = 1.52 + 2.72 + 4.82 - (1.5 × 2.7) - (2.7 × 4.8) - (4.8 × 1.5)

ओळख लागू करून, आपल्याला मिळते:

a + b + c = 1.5 + 2.7 + 4.8 = 9

∴ पदावलीचे सरलीकृत मूल्य 9 आहे.

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