Question
Download Solution PDFदिलेल्या आकृतीमध्ये, जर PA आणि PB हे केंद्र O असलेल्या वर्तुळाच्या स्पर्शिका असतील जसे की ∠APB = 54°, तर ∠ OBA = ________.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिलेल्याप्रमाणे:
PA आणि PB हे केंद्र O असलेल्या वर्तुळाच्या स्पर्शिका आहेत जसे की ∠APB = 54°
गणना:
आपल्याला माहित आहे की त्रिज्या आणि स्पर्शिका त्यांच्या संपर्क बिंदूवर लंब असतात.
तर,
∠PAO = ∠PBO = 90°
तर,
∠AOB = 360 - 54 - 180
⇒ 126°
तसेच AO = OB = त्रिज्या
तर, ∠OAB = ∠OBA = 54/2
⇒ 27°
∴ आवश्यक उत्तर 27° आहे
Last updated on Jul 16, 2025
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