Question
Download Solution PDFपायाच्या क्षेत्रफळाच्या दुप्पट वक्र पृष्ठफळ असलेल्या घन शंकूची तिरकस उंची 6√3 सेमी आहे. त्याची उंची किती आहे?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिलेले आहे:
शंकूचे वक्र पृष्ठफळ = 2 × शंकूच्या पायाचे क्षेत्रफळ
वापरलेली संकल्पना:
वापरलेले सूत्र
शंकूची तिरकस उंची = √r2 + h2
शंकूचे वक्र पृष्ठफळ = πrl
गणना:
शंकूची त्रिज्या r एकक असे मानू.
⇒ πrl = 2πr2
⇒ l = 2r
⇒ r = 6√3/2
⇒ r = 3√3
शंकूची तिरकस उंची (l) = √r2 + h2
⇒ 6√32 = 3√32 + h2
⇒ h2 = 108 - 27 = 81
⇒ h = 9 सेमी
∴ उत्तर 9 सेमी आहे.
Last updated on Jun 25, 2025
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