In a simultaneous throw of two dice, what is the probability of getting a total of 7?

(a) \(\frac{1}{6}\)

(b) \(\frac{1}{4}\)

(c) \(\frac{2}{3}\)

(d) \(\frac{3}{4}\)

Calculation:

The favourable outcomes for a total of 7 are:

⇒ (1,6), (2,5), (3,4), (4,3), (5,2), (6,1)

Number of favorable outcomes = 6

Probability of an event = (Number of favorable outcomes) / (Total number of possible outcomes)

⇒ Probability of getting a total of 7 = 6 / 36

⇒ Probability of getting a total of 7 = 1 / 6

∴ The correct answer is option 1.