In a right triangle for an acute angle x, if sin x = \(\frac{3}{7}\), then find the value of cosx.

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SSC CGL 2023 Tier-I Official Paper (Held On: 26 Jul 2023 Shift 2)
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  1. \(\frac{2}{7}\)
  2. \(\frac{3}{4}\)
  3. \(\frac{1}{\sqrt3}\)
  4. \(\frac{2(\sqrt{10})}{7}\)

Answer (Detailed Solution Below)

Option 4 : \(\frac{2(\sqrt{10})}{7}\)
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Detailed Solution

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Given:

In a right triangle for an acute angle x, if sin x = \(\frac{3}{7}\)

Calculation:

So perpendicular is 3 unit and hypotenuse is 7 units

So base is, √72 - 32 = 40 units

⇒ 2√10 units

As we know, cosx = Base / hypotenuse 

So, cosx= \(\frac{2(\sqrt{10})}{7}\)

The correct option is 4

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