Question
Download Solution PDFIf α and β are the roots of the polynomial f(x) = x2 + x + 1 then the value of \(\rm \frac{1}{\alpha}+\frac{1}{\beta}\) will be :
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept -
If α and β are the roots of the polynomial f(x) = ax2 + bx + c then
sum of roots = -b/a
product of roots = c/a
Explanation -
Now we have -
If α and β are the roots of the polynomial f(x) = x2 + x + 1
then α + β = -1 .....(i)
and α.β = 1...... (ii)
Now we want to find the value of \(\rm \frac{1}{\alpha}+\frac{1}{\beta}\)
= \(\frac{\alpha+\beta}{\alpha.\beta}\)
Now put the value of equation (i) and (ii) we get -
= -1/1 = -1
Hence option (3) is true.
Last updated on Jan 29, 2025
-> The Bihar STET 2025 Notification will be released soon.
-> The written exam will consist of Paper-I and Paper-II of 150 marks each.
-> The candidates should go through the Bihar STET selection process to have an idea of the selection procedure in detail.
-> For revision and practice for the exam, solve Bihar STET Previous Year Papers.