निम्नलिखित में से कौन-सा कथन सही है?

I. 1002 - 992 + 982 - 972 + 962 - 952 + 942 - 932 + ...... + 22 - 12 का मान 5050 है।

II. यदि 8x + \(\frac{8}{x}\)= -16 और x < 0 है, तब x197 + x-197 का मान 2 है।

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SSC CGL 2022 Tier-I Official Paper (Held On : 02 Dec 2022 Shift 4)
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  1. केवल I
  2. केवल II
  3. I और II दोनों
  4. न तो I और न ही II

Answer (Detailed Solution Below)

Option 1 : केवल I
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Detailed Solution

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कथन I:

1002 - 992 + 982 - 972 + 962 - 952 + 942 - 932 + ...... + 22 - 12

⇒ (1002 - 992) + (982 - 972) + (962 - 952) + (942 - 932) + ...... + (22 - 12)

⇒ (100 - 99)(100 + 99) + (98 - 97)(98 + 97) + (96 - 95)(96 + 95) + (94 - 93)(94 + 93) + ...... + (2 - 1)(2 + 1)

⇒ 1(100 + 99) + 1(98 + 97) + 1(96 + 95) + 1(94 + 93) + ...... + 1(2 + 1)

⇒ 100 + 99 + 98 + 97 + 96 + 95 + 94 + 93 + ...... + 2 + 1

अब,

हम जानते हैं कुछ क्रमागत पदों की संख्या n = n(n + 1)/2 

इसलिए, [100(100 + 1)]/2

⇒ 50 × 101

⇒ 5050

इसलिए, कथन I सही है।

कथन II:

यदि 8x + \(\frac{8}{x}\)= -16

⇒ x + \(\frac{1}{x}\) = - 2    [दोनों पक्षों से 8 को भाग देने पर​]

अब, x = - 1 के लिए,

x + \(\frac{1}{x}\) = - 2 संतुष्ट है।

अब,

x197 + x-197 = x197\(\frac{1}{x^{197}}\)

⇒ (- 1)197 + \(\frac{1}{(-1)^{197}}\)

⇒ - 1 - 1

⇒ - 2

इसलिए, कथन II सही नहीं है। 

∴ सही उत्तर विकल्प 1 है।

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