Question
Download Solution PDF\(\left| {\begin{array}{*{20}{c}} 1&1&1\\ 1&{1 + {\rm{x}}}&1\\ 1&1&{1 + {\rm{y}}} \end{array}} \right|\) का मान क्या है?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFधारणा:
प्राथमिक पंक्ति या स्तंभ रूपांतरण आव्यूह के सारणिक के मूल्य को नहीं बदलते हैं।
गणना:
\(\left| {\begin{array}{*{20}{c}} 1&1&1\\ 1&{1 + {\rm{x}}}&1\\ 1&1&{1 + {\rm{y}}} \end{array}} \right|\)
R2 → R2 – R1, R3 → R3 – R1 लागू करके हमें मिलता है
\(= \left| {\begin{array}{*{20}{c}} 1&1&1\\ 0&{\rm{x}}&0\\ 0&0&{\rm{y}} \end{array}} \right|\)
अब C1 के साथ विस्तार करके
= 1 (xy – 0) – 0 + 0 = xy
Last updated on May 30, 2025
->UPSC has released UPSC NDA 2 Notification on 28th May 2025 announcing the NDA 2 vacancies.
-> A total of 406 vacancies have been announced for NDA 2 Exam 2025.
->The NDA exam date 2025 has been announced for cycle 2. The written examination will be held on 14th September 2025.
-> Earlier, the UPSC NDA 1 Exam Result has been released on the official website.
-> The selection process for the NDA exam includes a Written Exam and SSB Interview.
-> Candidates who get successful selection under UPSC NDA will get a salary range between Rs. 15,600 to Rs. 39,100.
-> Candidates must go through the NDA previous year question paper. Attempting the NDA mock test is also essential.