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(4x + 1)2 − (4x + 3) (4x − 1)

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SSC CGL 2023 Tier-I Official Paper (Held On: 24 Jul 2023 Shift 2)
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  1. (4x + 1)
  2. 4
  3. (4x − 3)
  4. 4x

Answer (Detailed Solution Below)

Option 2 : 4
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Detailed Solution

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प्रयुक्त सूत्र

(a + b)2 = a2 + b2 + 2ab

गणना

(4x + 1)2 − (4x + 3) (4x − 1)

⇒ 16x2 + 1 + 2 × 4x × 1 - (16x2 - 4x + 12x - 3)

⇒ 1 + 8x × 1 - 8x + 3

⇒ 4

अभीष्ट मान 4 है

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