एक शंकु की त्रिज्या 5 सेमी और ऊंचाई 12 सेमी है। शंकु का वक्रपृष्ठीय क्षेत्रफल और इसके आधार के क्षेत्रफल का अनुपात ज्ञात कीजिये।

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  1. 4 : 5
  2. 14 : 5
  3. 12 : 5
  4. 13 : 5

Answer (Detailed Solution Below)

Option 4 : 13 : 5

Detailed Solution

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दिया गया है:

शंकु की त्रिज्या = 5 सेमी

शंकु की ऊंचाई = 12 सेमी

सूत्र:

शंकु का वक्रपृष्ठीय क्षेत्रफल = πrl

शंकु के आधार का क्षेत्रफल = πr2

l2 = r2 + h2

गणना:

F2 Savita Defence 29-12-22 D1

l2 = r2 + h2

⇒ l2 = 52 + 122

⇒ l2 = 25 + 144

⇒ l = √169

⇒ l = 13 सेमी

∴ अपेक्षित अनुपात = πrl : πr2

⇒ l : r

⇒ 13 : 5

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