चित्र में दिखाए गए LC परिपथ में प्रारंभिक धारा शून्य है, संधारित्र के आर-पार प्रारंभिक वोल्टेज 100 V है। स्विच S को t = 0 सेकंड पर बंद कर दिया जाता है। परिपथ में धारा है

F3 U.B Madhu 29.10.19 D 1

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ISRO Scientist Electrical 2018 Paper
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  1. 7.07 sin (7.07 x 103 t)
  2. 0.707 cos (7.07 x 103 t)
  3. 0.707 sin (7.07 x 103 t)
  4. 7.07 cos (7.07 x 103 t)

Answer (Detailed Solution Below)

Option 3 : 0.707 sin (7.07 x 103 t)

Detailed Solution

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सिद्धांत:

एक LC परिपथ में, परिपथ में प्रवाहित होने वाली धारा निम्न द्वारा दी जाती है,

\(i\left( t \right) = {V_s}\sqrt {\frac{C}{L}} \sin {\omega _0}t\)

जहाँ, V V में आपूर्ति वोल्टेज है

C F में धारिता है

L H में प्रेरकत्व है

ω0 rad/sec में अनुनाद आवृत्ति है

\({\omega _0} = \frac{1}{{\sqrt {LC} }}\)

गणना:

दिए गए परिपथ से, VS = 100 V

C = 1 μF

L = 20 mH

\({V_s}\sqrt {\frac{C}{L}} = 100 \times \sqrt {\frac{{1 \times {{10}^{ - 6}}}}{{20 \times {{10}^{ - 3}}}}} = 0.707\)

\({\omega _0} = \frac{1}{{\sqrt {20 \times {{10}^{ - 3}} \times 1 \times {{10}^{ - 6}}} }} = 7.07 \times {10^3}\)

\(i\left( t \right) = 0.707\sin \left( {7.07 \times {{10}^3}t} \right)\)
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