वक्र y = t2 + 2t और x = t3 में t = 5 पर ढलान \(\rm dy\over dx\) ज्ञात कीजिए। 

  1. \(\rm \frac{4}{5}\)
  2. \(\rm \frac{4}{3}\)
  3. \(\rm \frac{12}{5}\)
  4. \(\rm \frac{4}{25}\)

Answer (Detailed Solution Below)

Option 4 : \(\rm \frac{4}{25}\)
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Detailed Solution

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संकल्पना:

प्राचलिक रूप:

यदि f(x) और g(x), x में फलन है, तो

\(\rm df(x)\over dg(x)\) = \(\rm \frac{df(x)\over dx}{dg(x)\over dx}\) 

 

गणना:

दिया गया है y = t2 + 2t

\(\rm {dy\over dt}\) = 2t + 2

साथ ही x = t3

\(\rm dx\over dt\) = 3t2 

अब \(\rm dy\over dx\) = \(\rm \frac{dy\over dt}{dx\over dt}\) 

\(\rm dy\over dx\) = \(\rm \frac{2t +2}{3t^2}\)

t = 5 पर,

\(\rm {dy\over dx}\) = \(\rm \frac{2(5) +2}{3(5)^2}\) = \(\rm \frac{12}{75}\) = \(\rm \frac{4}{25}\)

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