Question
Download Solution PDFयदि x और \(\frac{1}{x}\) (x ≠ 0) का औसत m है, तो x2 और \(\rm \frac{1}{x^2}\)का औसत है :
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिया गया:
x और 1/x का औसत = m
प्रयुक्त सूत्र:
a और b का औसत = (a + b)/2
गणना:
एम = (एक्स + 1/एक्स)/2
⇒ x + 1/x = 2मी
अब, x 2 और 1/x 2 का औसत = (x 2 + 1/x 2 )/2
एक्स 2 + 1/x 2 = (एक्स + 1/x) 2 - 2
⇒ x 2 + 1/x 2 = (2मी) 2 - 2
⇒ x 2 और 1/x 2 का औसत = [(2m) 2 - 2]/2
⇒ = 2मी 2 - 1
∴ सही उत्तर विकल्प (1) है।
Last updated on Jun 19, 2025
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