Question
Download Solution PDFयदि f(2x) = 4x2 + 1 है, तो x के कितने वास्तविक मानों के लिए f(2x), f(x) और f(4x) का गुणोत्तर माध्य (GM) होगा?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFव्याख्या:
f(2x) = 4x2 + 1
⇒f(x) = x2 + 1
⇒ f(4x) = 16x2 + 1
⇒ (4x2 + 1)2 = (x2 + 1) × (16x2 + 1) [f(2x), f(x) और f(4x) का GM है]
⇒ 16x4 + 8x2 + 1 = 16x4 + x2 + 16x2 + 1
⇒ 16x4 + 8x2 + 1 = 16x4 + 17x2 + 1
⇒ 9x2 = 0
⇒x2 = 0
⇒x = 0
इस प्रकार x का एक वास्तविक मान संभव है
∴ विकल्प (c) सही है।
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