सबसे बड़े गोले का आयतन ज्ञात कीजिए जिसे 21 सेमी भुजा वाले घन से काटकर बनाया गया है।

This question was previously asked in
NTPC CBT-I (Held On: 11 Jan 2021 Shift 1)
View all RRB NTPC Papers >
  1. 4851 सेमी3
  2. 4158 सेमी3
  3. 5841 सेमी3
  4. 8514 सेमी3

Answer (Detailed Solution Below)

Option 1 : 4851 सेमी3
Free
RRB NTPC Graduate Level Full Test - 01
100 Qs. 100 Marks 90 Mins

Detailed Solution

Download Solution PDF

दिया गया है: 

घन की भुजा = 21 सेमी

प्रयुक्त सूत्र:

गोले का आयतन = 4/3πr3

गणना:

 

21 सेमी भुजा वाले घन से जो सबसे बड़ा गोला बनाया जा सकता है उसका व्यास 21 सेमी के बराबर होगा।

गोले की त्रिज्या = 21/2 सेमी

गोले का आयतन = 4/3 × 22/7 × 21/2 × 21/2 × 21/2

⇒ 11 × 21 × 21 

⇒ 4851 सेमी3

∴ अभीष्ट परिणाम 4851 सेमीहै।

Latest RRB NTPC Updates

Last updated on Jul 22, 2025

-> RRB NTPC Undergraduate Exam 2025 will be conducted from 7th August 2025 to 8th September 2025. 

-> The RRB NTPC UG Admit Card 2025 will be released on 3rd August 2025 at its official website.

-> The RRB NTPC City Intimation Slip 2025 will be available for candidates from 29th July 2025. 

-> Check the Latest RRB NTPC Syllabus 2025 for Undergraduate and Graduate Posts. 

-> The RRB NTPC 2025 Notification was released for a total of 11558 vacancies. A total of 3445 Vacancies have been announced for Undergraduate posts while a total of 8114 vacancies are announced for Graduate-level posts in the Non-Technical Popular Categories (NTPC).

-> Prepare for the exam using RRB NTPC Previous Year Papers.

->  HTET Admit Card 2025 has been released on its official site

More Solid Figures Questions

More Mensuration Questions

Hot Links: teen patti master online teen patti party teen patti win teen patti tiger