Question
Download Solution PDFतार की एक वृत्ताकार कुंडल में 500 फेरे हैं, प्रत्येक की त्रिज्या 6.0 सेमी है, जिसमें 0.30 A की धारा प्रवाहित हो रही है। कुंडल के केंद्र में चुंबकीय क्षेत्र B का परिमाण ज्ञात कीजिए।
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFसंकल्पना:
एक वृत्ताकार कुंडल वहन धारा के केंद्र में चुंबकीय क्षेत्र के लिए सूत्र का उपयोग करने पर
\(B = \frac{μ_0}{4π}× \frac{2π N I}{r}\)
जहां μ0 = 4π × 10-7Wb/Am, N फेरों की संख्या है, I धारा तीव्रता है और r कुंडल की त्रिज्या है
गणना:
दिया गया है N = 500, I = 0.30A और r = 0.06m
\(B = 10^{-7} × \frac{2\pi × 500 × 0.30}{0.06}\)
B = 1.57 × 10-3T
Last updated on Jun 19, 2025
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