Find the general solution of the equation 4 sin 3x = 2?

  1. n × (π/3) + (- 1)n × (π/18), where n ∈ Z
  2. n × (- π/3) + (- 1)n × (π/18), where n ∈ Z
  3. n × (π/3) + (- 1)n × (5π/18), where n ∈ Z
  4. None of these

Answer (Detailed Solution Below)

Option 1 : n × (π/3) + (- 1)n × (π/18), where n ∈ Z
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NDA 01/2025: English Subject Test
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Detailed Solution

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Concept:

If sin θ = sin α then θ = nπ + (- 1)n α, α ∈ [-π/2, π/2], n ∈ Z.

T-Ratios

30°

45°

60°

90°

Sin

0

1/2

1/√2

√3/2

1

Cos

1

√3/2

1/√2

1/2

0

Tan

0

1/√3

1

√3

Not defined

 

Calculation:

Given: 4 sin 3x = 2

⇒ sin 3x = ½

As we know that, sin (π/6) = ½

⇒ sin 3x = sin (π/6)

As we know that, if sin θ = sin α then

θ = nπ + (- 1)n α, α ∈ [-π/2, π/2], n ∈ Z.

⇒ 3x = nπ + (- 1)n × (π/6), where n ∈ Z.

⇒ x = n × (π/3) + (- 1)n × (π/18), where n ∈ Z.
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