Question
Download Solution PDFConsider a complex exponential sequence \({e^{j{\omega _0}n}}\) with frequency ω0. Suppose ω0 = 1, then
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
Any discrete signal is said to be periodic if:
\(\frac{{{\omega _0}}}{{2\pi }}\) is a rational number \(\left( {\frac{M}{N}} \right)\)
Calculation:
Given signal is \({e^{j{\omega _0}n}}\), ω0 = 1 rad / sec
\(\frac{{{\omega _0}}}{{2\pi }} = \frac{1}{{2\pi }}\)
Since this is not a rational number, so it is not periodic at all.
Note:
Continuous sinusoidal and complex sinusoids are periodic for every value of ‘ω0’, but discrete-time signals are periodic only if \(\frac{{{\omega _0}}}{{2\pi }}\) is a rational number \(\frac{M}{N}\).
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