Question
Download Solution PDFA point charge of +12 μC is at a distance 6 cm vertically above the centre of a square of side 12 cm as shown in figure. The magnitude of the electric flux through the square will be ______ × 103 Nm2/C.
Answer (Detailed Solution Below) 226
Detailed Solution
Download Solution PDFCONCEPT:
Gauss's law, states that the total electric flux enclosed in the given material is equal to the ratio of the total charge enclosed to the permittivity of the given material.It si written as;
Here, Qtotal is the total charge enclosed and
EXPLANATION:
Given :Charge, Q = +12
Distance, r = 6 cm
According to gauss's law, the flux of the 12-sided square is written as;
Now, on putting the given values we have,
⇒
Last updated on May 23, 2025
-> JEE Main 2025 results for Paper-2 (B.Arch./ B.Planning) were made public on May 23, 2025.
-> Keep a printout of JEE Main Application Form 2025 handy for future use to check the result and document verification for admission.
-> JEE Main is a national-level engineering entrance examination conducted for 10+2 students seeking courses B.Tech, B.E, and B. Arch/B. Planning courses.
-> JEE Mains marks are used to get into IITs, NITs, CFTIs, and other engineering institutions.
-> All the candidates can check the JEE Main Previous Year Question Papers, to score well in the JEE Main Exam 2025.