A point charge of +12 μC is at a distance 6 cm vertically above the centre of a square of side 12 cm as shown in figure. The magnitude of the electric flux through the square will be ______ × 103 Nm2/C.

Answer (Detailed Solution Below) 226

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JEE Main 04 April 2024 Shift 1
90 Qs. 300 Marks 180 Mins

Detailed Solution

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CONCEPT:

Gauss's law, states that the total electric flux enclosed in the given material is equal to the ratio of the total charge enclosed to the permittivity of the given material.It si written as;

Here, Qtotal is the total charge enclosed and  is the permittivity of the material.

EXPLANATION:

Given :Charge, Q = +12 C

Distance, r = 6 cm

According to gauss's law, the flux of the 12-sided square is written as;

Now, on putting the given values we have,

⇒  Nm2/C

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