A point charge of +12 μC is at a distance 6 cm vertically above the centre of a square of side 12 cm as shown in figure. The magnitude of the electric flux through the square will be ______ × 10³ Nm²/C.

CONCEPT:

Gauss's law, states that the total electric flux enclosed in the given material is equal to the ratio of the total charge enclosed to the permittivity of the given material.It si written as;

\(\phi = \frac{Q_{total}}{\epsilon_o}\)

Here, Q_total is the total charge enclosed and \(\epsilon_o\) is the permittivity of the material.

EXPLANATION:

Given :Charge, Q = +12 \(\mu\)C

Distance, r = 6 cm

According to gauss's law, the flux of the 12-sided square is written as;

\(\phi = \frac{Q}{6\epsilon_o}\)

Now, on putting the given values we have,

\(\phi = \frac{12\times 10^{-6}}{6\times 8.85\times 10^{-12}}\)

⇒ \(\phi = 226 \times 10^{3}\) Nm²/C