Train Crossing a Platform MCQ Quiz - Objective Question with Answer for Train Crossing a Platform - Download Free PDF

Last updated on Jun 27, 2025

Train Problems is a vast, common and requisite section. It’s further divided into more sub-topics such as Train Crossing a Platform. Train Crossing a Platform MCQs Quiz are quite common in entrance and aptitude tests such as in bank exams, SSC, CAT, PO, interviews and quiz tests, etc. Recruitments have allocated a fair number of weightage to Train Crossing a Platform questions. In this article, you will find some Train Crossing Platform questions, its solutions, explanations and tricks.

Latest Train Crossing a Platform MCQ Objective Questions

Train Crossing a Platform Question 1:

Two trains A and B are of the same length. Train A can cross a bridge of length 150 meters in 30 seconds, and train B can cross the same bridge in 15 seconds. If train A can cross a pole in 15 seconds, then find the time taken by both trains to cross each other while running in opposite directions. 

  1. 8 seconds
  2. 10 seconds
  3. 12 seconds
  4. 15 seconds
  5. 19 seconds

Answer (Detailed Solution Below)

Option 2 : 10 seconds

Train Crossing a Platform Question 1 Detailed Solution

Given:

Length of bridge = 150 meters

Train A takes 30 seconds to cross the bridge

Train B takes 15 seconds to cross the same bridge

Train A takes 15 seconds to cross a signal post

Both trains are of equal length

Calculation:

Let length of each train = L meters

Train A:

Time to cross bridge = 30 sec ⇒ Distance = L + 150

⇒ Speed of Train A = (L + 150) ÷ 30

Also, Train A crosses a signal post (length L) in 15 sec

⇒ Speed of Train A = L ÷ 15

Equating the two speeds:

(L + 150) ÷ 30 = L ÷ 15

⇒ (L + 150) = 2L

⇒ 150 = 2L - L = L

So, Length of each train = 150 meters

Speed of Train A:

⇒ Speed = L ÷ 15 = 150 ÷ 15 = 10 m/s

Speed of Train B:

Total distance Train B covers = L + 150 = 150 + 150 = 300 meters

Time = 15 seconds

⇒ Speed = 300 ÷ 15 = 20 m/s

When two trains cross each other in opposite directions:

Total distance = Sum of lengths = 150 + 150 = 300 meters

Relative speed = 10 + 20 = 30 m/s

Time = Distance ÷ Relative speed = 300 ÷ 30 = 10 seconds

Thus, teh correct answer is 10 seconds.

Train Crossing a Platform Question 2:

Train X, running at a speed of 72 km/hr, crosses a bridge that is one-third of its length in 20 seconds. It then overtakes Train Y, which is moving at 24 km/hr, in 45 seconds. Find the sum of the length of the bridge and the length of Train Y.

  1. 350 meters
  2. 400 meters
  3. 500 meters
  4. 650 meters
  5. 900 meters

Answer (Detailed Solution Below)

Option 2 : 400 meters

Train Crossing a Platform Question 2 Detailed Solution

Calculation:

Speed of Train X = 72 km/h = 72  ×1000 / 3600 = 20 m/s

Train X crosses a bridge 1/3 of its own length in 20 seconds

Then it overtakes Train Y speed = 24 km/h = 6.67 m/s in 45 seconds

We have to find: Length of the bridge + Length of Train Y

Let the length of Train X = L meters.

Then the length of the bridge = L/3

Train X crosses the bridge

Time = 20 seconds

Speed = 20 m/s

So, total distance covered = 20 × 20 = 400 meters

Since it covers its own length + the bridge's length:

L + L/3 = 400

4L / 3 = 400

L = 400 × 3 / 4 = 300 m 

So:

Length of Train X = 300 m

Length of Bridge = 13 × 300 = 100 m

rain X overtakes Train Y:

Relative speed = 20 − (24 × 1000 / 3600) = 20 − 6.67 = 13.33 m/s

Time taken to overtake = 45 seconds

Distance covered = 13.33 × 45 = 600 meters

When Train X overtakes Train Y, it covers:

→ Its own length 300 m + Train Y's length = 600 m

⇒ Length of Train Y = 600 − 300 = 300 m 

Find sum of bridge and Train Y's lengths

Bridge = 100 m

Train Y = 300 m

Sum = 100 + 300 = 400 meters

Thus, the correct answer is 400 meters.

Train Crossing a Platform Question 3:

Train A and B cross a 120m platform. B takes 3 sec less than A. Combined length of train A and B is 600m. Speed ratio of train A and B is 3 : 2. Find speed of train B.

  1. 64
  2. 90
  3. 54
  4. 72
  5. CND

Answer (Detailed Solution Below)

Option 5 : CND

Train Crossing a Platform Question 3 Detailed Solution

Calculation

Let speeds: A = 3x, B = 2x

Let length A = a

→ then B = 600 - a

Time = length / speed

→ a/3x - (600 - a)/2x = 3

We have two variable and only one equation. So, answer cannot be determined.  

Train Crossing a Platform Question 4:

A train of length 350 m crosses a bridge of length 250 m in 20 seconds. What is the speed of the train (in km/h)?

  1. 95
  2. 72
  3. 108
  4. 88

Answer (Detailed Solution Below)

Option 3 : 108

Train Crossing a Platform Question 4 Detailed Solution

Given:

Length of train = 350 m

Length of bridge = 250 m

Total time = 20 seconds

Formula used:

Speed = Total Distance / Time

Total Distance = Length of train + Length of bridge

Calculation:

Total Distance = 350 + 250 = 600 m

Speed (in m/s) = Total Distance / Time

⇒ Speed = 600 / 20

⇒ Speed = 30 m/s

Speed (in km/h) = (30 × 18) / 5

⇒ Speed = 108 km/h

∴ The correct answer is option (3).

Train Crossing a Platform Question 5:

Train P, which is ‘d’ meters long, takes the same time to pass a 300-meter-long platform as Train Q, which is (d + 200) meters long, takes to pass a 500-meter-long platform. If the ratio of their speeds (Train P to Train Q) is 5:9, then what is the value of d?

  1. 240
  2. 220
  3. 280
  4. 200
  5. 250

Answer (Detailed Solution Below)

Option 4 : 200

Train Crossing a Platform Question 5 Detailed Solution

Calculation

Let speed of train P and Q be 5x m/sec. & 9x m/sec. respectively

ATQ,

[ (d+300) / 5x] =  [(d+700) / 9x]

So, 9d + 2700 = 5d + 3500

So, 4d = 800

So, d = 200

Top Train Crossing a Platform MCQ Objective Questions

Running at a speed of 60 km per hour, a train passed through a 1.5 km long tunnel in two minutes, What is the length of the train ?

  1. 250 m
  2. 500 m
  3. 1000 m
  4. 1500 m

Answer (Detailed Solution Below)

Option 2 : 500 m

Train Crossing a Platform Question 6 Detailed Solution

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Given:

Speed is 60 km per hour,

Train passed through a 1.5 km long tunnel in two minutes

Formula used:

Distance = Speed × Time

Calculation:

Let the length of the train be L

According to the question,

Total distance = 1500 m + L

Speed = 60(5/18)

⇒ 50/3 m/sec

Time = 2 × 60 = 120 sec

⇒ 1500 + L = (50/3)× 120

⇒ L = 2000 - 1500

⇒ L = 500 m

∴ The length of the train is 500 m.

A train crossed a 110 m long platform in 13.5 seconds and a 205 m long platform in 18.25 seconds. What was the speed of the train?

  1. 72 km/h
  2. 66 km/h
  3. 69 km/h
  4. 75 km/h

Answer (Detailed Solution Below)

Option 1 : 72 km/h

Train Crossing a Platform Question 7 Detailed Solution

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Let the length of train be x m.

⇒ Speed of train = (length of platform + length of train)/time

According to question,

⇒ (110 + x)/ 13.5 = (205 + x)/18.25

⇒ (110 + x)/2.7 = (205 + x)/3.65

⇒ 401.5 + 3.65x = 553.5 + 2.7x

⇒ 0.95x = 152

⇒ x = 160

⇒ Speed of train = (110 + 160)/13.5 = 20 m/sec = 20 × (18/5) = 72 km/hr

A 1200 m long train crosses a tree in 120 sec, how much time will it take to pass a platform 700 m long?

  1. 10 sec
  2. 50 sec
  3. 80 sec
  4. 190 sec

Answer (Detailed Solution Below)

Option 4 : 190 sec

Train Crossing a Platform Question 8 Detailed Solution

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Given:

Length of a train is 1200m

Train took 120 sec to cross a tree

Length of a platform is 700m

Formula USed:

Speed = Distance/Time 

Calculation:

Speed = 1200/120 = 10 m/sec

Total distance = 1200 + 700 = 1900 m

Time = distance/speed = 1900/10 = 190 sec

∴ Time required to cross a platform is 190 sec.

A train passes a platform in 48 seconds and a passenger standing on the platform in 30 seconds. If the speed of the train is 72 km/hr, what is the length of the platform?

  1. 440m
  2. 380m
  3. 360m
  4. 400m

Answer (Detailed Solution Below)

Option 3 : 360m

Train Crossing a Platform Question 9 Detailed Solution

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Given:

Speed of the train = 72km/hr

The train passes the platform in 48 sec and the passenger in 30 sec

Concept used:

Speed = distance/time

While a train crossing a man it actually crossing it's own length.

Calculation:

Speed of the train is 72 km/hr = 72 × (5/18) = 20 m/sec

Length of train = speed × time

⇒ 20 × 30 = 600 m

Now, accordingly

\(20 = \;\frac{{x + 600}}{{48}}\)

⇒ \(20 × 48 = x + 600\)

⇒ x = 960 - 600

⇒ x = 360

∴ The length of the platform is 360 meter.

The time taken for the tail end of a train to cross a pole is 53 seconds. If the length of the train is 110 m and speed of the train is 36 km/hr, find the initial distance of the pole from the front end of the train.

  1. 420 m
  2. 530 m
  3. 640 m
  4. 1798 m

Answer (Detailed Solution Below)

Option 1 : 420 m

Train Crossing a Platform Question 10 Detailed Solution

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⇒ Speed = Distance/time

⇒ Speed of train = 36 × (5/18) = 10m/s

⇒ Distance covered in 53 seconds = 10 × 53 = 530 m

⇒ Length of train = 110m

∴ The initial distance of the pole from the front end of the train = 530 – 110 = 420 m.

A 250 meters long train crosses a bridge 750 meters long in 20 seconds and crosses a platform in 15 seconds. Find the length of the platform.

  1. 350 m
  2. 450 m
  3. 500 m
  4. 800 m

Answer (Detailed Solution Below)

Option 3 : 500 m

Train Crossing a Platform Question 11 Detailed Solution

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Given:

A 250 meters long train crosses a bridge 750 meters long in 20 seconds

And crosses a platform in 15 seconds.

Formula Used:

Distance = Speed × Time

Calculation:

Let the speed of the train be S

And let the length of the platform be x

According to the question,

250 + 750 = S × 20

⇒ S = 1000/20

⇒ 50 m/sec

Now, Again according to the question

The train crosses the platform in 15 seconds

250 + x = 50 × 15

⇒ x = 750 - 250

⇒ x = 500 m

∴ The length of the platform is 500 m.

A train crosses a pole in 5 seconds and crosses the tunnel in 20 seconds. If the speed of the train 90 m/s, then find the length of the tunnel.

  1. 1350 m
  2. 900 m
  3. 1200 m
  4. 800 m

Answer (Detailed Solution Below)

Option 1 : 1350 m

Train Crossing a Platform Question 12 Detailed Solution

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Given:

Time to cross the pole = 5 sec

Time to crosses the tunnel = 20 sec

Formula used:

Speed = Distance/Time

Calculation:

Let the length of the tunnel be x m and the length of the train be y m

Time = Distance/Speed

⇒ 5 = (y/90)

⇒ y = 450 m

Time to crosses the tunnel = Distance/Speed

⇒ 20 = (y + x)/90

⇒ 20 × 90 = (450 + x)

⇒ x = 1800 - 450 = 1350

∴ The length of the tunnel is 1350 m.

A train crosses a pole in 12 sec, and a bridge of length 170 m in 36 sec. Then the speed of the train is:

  1. 30.75 km/h
  2. 25.5 km/h
  3. 32.45 km/h
  4. 10.8 km/h

Answer (Detailed Solution Below)

Option 2 : 25.5 km/h

Train Crossing a Platform Question 13 Detailed Solution

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Formula used:

Speed = Distance / Time

(1 m/s) × (18/5) = 1 km/hr

Shortcut Trick

If train cross its length in 12 seconds and 170 m bridge in (36 - 12 = 24) seconds.

Speed of train = [170/24] × [18/5] = 25.5 km/hr

 Alternate Method

Let the length of the train be x m.

As we know,

Speed = Distance/time

Speed (v) = x/12     

x = 12 v                      -----(1)

Again,

v = (x + 170)/36          -----(2)

From equation (1)

v = (12v + 170)/36

⇒ 36v = 12v + 170

⇒ 24v = 170

⇒ v = 170/24 m/s 

⇒ v = (170/24) × (18/5) km/hr

∴ Speed = 25.5 km/hr

A train crosses a 375 m long platform in 27 seconds. How long was the train if it was travelling at the speed of 70 km/h?

  1. 525 m
  2. 140 m
  3. 160 m
  4. 150 m

Answer (Detailed Solution Below)

Option 4 : 150 m

Train Crossing a Platform Question 14 Detailed Solution

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Let length of train be A meter.

⇒ 70 kmph = 70 × 5/18 = 175/9 m/sec

A train crosses a 375 m long platform in 27 seconds,

⇒ 175/9 = (375 + A) /27

⇒ 375 + A = 175 × 3

⇒ A = 150

∴ The length of the train = 150 m

A train crosses a station platform in 36 seconds and crosses a man standing on the platform in 20 seconds. If the speed of the train is 54 km/h, what is the length of the platform?

  1. 360 m
  2. 240 m
  3. 120 m
  4. 300 m

Answer (Detailed Solution Below)

Option 2 : 240 m

Train Crossing a Platform Question 15 Detailed Solution

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Given:

A train crosses a station platform in 36 seconds

And crosses a man standing on the platform in 20 seconds

The speed of the train is 54 km/h

Formula Used:

Speed = Distance/Time

Calculation:

Let the length of the train be x m and the length of the platform be y m 

According to the question

54 × (5/18) = x/20

⇒ 15 × 20 = x

⇒ x = 300 m

Again, According to the question

⇒ 54 × (5/18) = (300 + y) /36

⇒ 15 × 36 = 300 + x

⇒ y = 540 – 300

⇒ y = 240

∴ The length of the platform is 240.

Shortcut Trick As given train cross its length in 20 seconds.

So the train cross the platform in = 36 – 20 = 16 seconds

The distance covered by train in 16 seconds = 54 × (5/18) × 16 = 240

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