Tabulation and Line Graph MCQ Quiz - Objective Question with Answer for Tabulation and Line Graph - Download Free PDF

Common Calculation

For shop A,

Number of copper items sold in shop A is 24.

Number of bronze items sold in shop A is 16.

So, total number of copper and bronze items sold in shop A is 24 + 16 = 40.

So, Ratio between total number of [ copper + bronze] items sold to number silver items sold.

So, Number of silver items sold in shop A is 40 × 4 /5 = 32

Similarly, we can calculate others values also, which is given in the table.

Calculation

In Shop D:

Copper = 36

→ Shop E = 36 × 1.25 = 45

Bronze = 24

→ Shop E = 24 × 1.125 = 27

Silver = 40

→ Shop E = 40 × 1.30 = 52

Total in Shop E = 45 + 27 + 52 = 124

Total in Shop C = 32 + 18 + 36 = 86

Difference = 124 – 86 = 38

Answer: 38

Common Calculation

For shop A,

Number of copper items sold in shop A is 24.

Number of bronze items sold in shop A is 16.

So, total number of copper and bronze items sold in shop A is 24 + 16 = 40.

So, Ratio between total number of [ copper + bronze] items sold to number silver items sold.

So, Number of silver items sold in shop A is 40 × 4 /5 = 32

Similarly, we can calculate others values also, which is given in the table.

Calculation

In Shop D:

Bronze = 24, Silver = 40 ⇒ Total = 64

Tin items = 25% more than 64 = 1.25 × 64 = 80

Now, tin = 80, copper = 36

Average = (80 + 36) ÷ 2 = 116 ÷ 2 = 58

Answer: 58

Common Calculation

For shop A,

Number of copper items sold in shop A is 24.

Number of bronze items sold in shop A is 16.

So, total number of copper and bronze items sold in shop A is 24 + 16 = 40.

So, Ratio between total number of [ copper + bronze] items sold to number silver items sold.

So, Number of silver items sold in shop A is 40 × 4 /5 = 32

Similarly, we can calculate others values also, which is given in the table.

Calculation

Copper in B + C = 30 + 32 = 62

Silver in B + C = 24 + 36 = 60

Difference = 62 – 60 = 2

Answer: 2

Common Calculation

For shop A,

Number of copper items sold in shop A is 24.

Number of bronze items sold in shop A is 16.

So, total number of copper and bronze items sold in shop A is 24 + 16 = 40.

So, Ratio between total number of [ copper + bronze] items sold to number silver items sold.

So, Number of silver items sold in shop A is 40 × 4 /5 = 32

Similarly, we can calculate others values also, which is given in the table.

Calculation

In Shop B:

Copper = 30 × 750 = 22,500

Bronze = 28 × 550 = 15,400

Silver = 24 × 1050 = 25,200

Total value = 22,500 + 15,400 + 25,200 = 63,100

Total items = 30 + 28 + 24 = 82

Average selling price = 63100 ÷ 82 = Rs. 769.51 (approx)

Answer: Rs. 770

Common Calculation

For shop A,

Number of copper items sold in shop A is 24.

Number of bronze items sold in shop A is 16.

So, total number of copper and bronze items sold in shop A is 24 + 16 = 40.

So, Ratio between total number of [ copper + bronze] items sold to number silver items sold.

So, Number of silver items sold in shop A is 40 × 4 /5 = 32

Similarly, we can calculate others values also, which is given in the table.

Calculation

In Shop A:

Total silver items = 32

Number of x-type silver items = 3m + 2

Number of y-type silver items = 2n + 6

So,

3m + 2 + 2n + 6 = 32

⇒ 3m + 2n = 24

Also, m + n = 10,

So, m = 4 and n = 6

⇒ Required ratio m : n

Answer: m : n = 4 : 6 = 2 : 3

Calculation:

The ratio of number of car A and car B in 2012 = 17 : 16

The production of car A in 2012 = 850

Let the ratio of number of car A and car B be 17x and 16x respectively

⇒ 17x = 850

⇒ x = 50

The production of car B = 16x = 16 × 50 = 800

The number of car A manufactured in 2014 = 630

Required ratio = (800 : 630)

⇒ 80 : 63

∴  The ratio of number of Car B manufactured in 2012 to the number of Car A manufactured in 2014 is 80 : 63

Given :

The students joined and left in different years 

Intial strength of school = 2000

Calculation :

Strength of school at the end of 2017 = 2000 + (375 - 250) + (350 - 425) + (400 - 220)

⇒ 2000 + 125 - 75 + 180 = 2230

∴ The answer is 2230.

Let the total number of employees in the the year 2005 be x

So, the total number of managers in 2005 = (80/100) × x = 0.8x

⇒ Total number of workers in 2005 = x – 0.8x = 0.2x

Hence, the number of male managers in 2005 = (5/8) × 0.8x = 0.5x

And the total number of employees in the the year 2006 be y

Also, So, the total number of managers in 2006 = (50/100) × y = 0.5y

⇒ Total number of workers in 2006 = y – 0.5y = 0.5y

Hence, the number of male managers in 2006 = (2/5) × 0.5y = 0.2y

As the number of workers is the same, we get:

0.2x = 0.5y

⇒ x = 2.5y      ----(i)

Using equation(i), the required ratio will become:

(0.5 × 2.5y)/0.2y = 25/4

∴ The reuqired ratio between the number of male managers in 2005 and 2006 is 25 ∶ 4

Formula used:

Percentage = (Part value/Original value) × 100

Calculation: 

Orders placed and delivered on Wednesday

⇒ 400 + 223 = 623

Orders placed and returned on Friday

⇒ 275 + 59.43

⇒ 334.43

Percentage

⇒ (623/334.43) × 100

⇒ 186.70% ≈ 186%

∴ The approximate percentage is 186%.

Calculation:

Total items returned on Tuesday and Wednesday = (60.75 + 28.99) thousand = 89740

Average of items returned on Tuesday and Wednesday = 89740/2 = 44870

∴ 44870

Females in the month June = 250 × 50/100 = 125

Females in the month July = 200 × 20/100 = 40

The average of the female in the month of June and July by Driver A = (125 + 40)/2 = 82.5

Percentage of males in the month June = 100 - 70 = 30

Males in the month June = 350 × 30/100 = 105

Percentage of males in the month of July = 100 - 40 = 60

Males in the month July = 250 × 60/100 = 150

The average of the Males in the month of June and July by Driver B = (105 + 150)/2 = 127.5

 The ratio of the average of the female in the month of June and July by Driver A to the average of the males in the same month by Driver B

= 82.5 : 127.5 = 11 : 17

Required average = Sum of observations/number of observations

Let the number of employees in the company during each of the year be x

So, the number of managers in the year 2005 = (80/100)x = 0.8x

Among them, the number of male managers = (5/8) × 0.8x = 0.5x

Similarly,

So, the number of managers in the year 2006 = (50/100)x = 0.5x

Among them, the number of male managers = (2/5) × 0.5x = 0.2x

So, the percentage decrease in the number of male managers = [(0.5x – 0.2x)/0.5x] × 100 = 60%

Given: Number of delivered orders after cancellation of C = 15

Ratio of cancelled orders of C and E  = 5 : 6

Total number of cancelled orders for C = Total number of delivered orders for C 

Percentage of delivered orders of E = 80%

Calculation: 

Number of cancelled order of C = 15

Number of cancelled order of E = 15/5 × 6 = 18

Percentage of cancelled orders of E = 20%

Total number of orders of E = 18/20 × 100 = 90

Calculations:

From the line graph given, we can get the total population of villages (M, N, O, P, Q ,and R).

From the table provided, We can find 4 parameters only:

1. Literate people of a particular village (Ratio of literate to illiterate)

2. Illiterate people of a particular village (Ratio of literate to illiterate)

3. Male population of a particular village (Percentage of male population)

4. Female population of a particular village (Percentage of male population)

All Data that can be derived from the Line graph and Tabulation is summarised below.

As we can see from the data we can't infer number of literate males.

Hence, The ratio can't be determined  

Individual Solution:

We can not find ratio of literate and illiterate male From M,N and O.

⇒ Male from village P, Q and R = 2000 + 2200 + 1800 = 6000

∴ The ratio can't be determined