Tabulation and Line Graph MCQ Quiz - Objective Question with Answer for Tabulation and Line Graph - Download Free PDF
Last updated on Jul 1, 2025
Latest Tabulation and Line Graph MCQ Objective Questions
Tabulation and Line Graph Question 1:
Comprehension:
The line graph shows the number of copper and bronze items sold in four different shops [A, B, C, and D].
The given table shows the ratio between total number of [ copper + bronze] items sold to number silver items sold.
Shop |
Ratio between total number of [ copper + bronze] items sold to number silver items sold. |
A |
5:4 |
B |
29:12 |
C |
25:18 |
D |
3:2 |
Number of copper, bronze and silver items sold in shop E is 25%, 12.5% and 30% more than the same in shop D. Find the difference between total number of items sold in shop E and C?
Answer (Detailed Solution Below)
Tabulation and Line Graph Question 1 Detailed Solution
Common Calculation
For shop A,
Number of copper items sold in shop A is 24.
Number of bronze items sold in shop A is 16.
So, total number of copper and bronze items sold in shop A is 24 + 16 = 40.
So, Ratio between total number of [ copper + bronze] items sold to number silver items sold.
So, Number of silver items sold in shop A is 40 × 4 /5 = 32
Similarly, we can calculate others values also, which is given in the table.
Shop |
Number of copper items sold |
Number of Bronze items sold |
Number of Silver items sold |
A |
24 |
16 |
32 |
B |
30 |
28 |
24 |
C |
32 |
18 |
36 |
D |
36 |
24 |
40 |
Calculation
In Shop D:
Copper = 36
→ Shop E = 36 × 1.25 = 45
Bronze = 24
→ Shop E = 24 × 1.125 = 27
Silver = 40
→ Shop E = 40 × 1.30 = 52
Total in Shop E = 45 + 27 + 52 = 124
Total in Shop C = 32 + 18 + 36 = 86
Difference = 124 – 86 = 38
Answer: 38
Tabulation and Line Graph Question 2:
Comprehension:
The line graph shows the number of copper and bronze items sold in four different shops [A, B, C, and D].
The given table shows the ratio between total number of [ copper + bronze] items sold to number silver items sold.
Shop |
Ratio between total number of [ copper + bronze] items sold to number silver items sold. |
A |
5:4 |
B |
29:12 |
C |
25:18 |
D |
3:2 |
Number of tin items sold in shop D is 25% more than the number of bronze and silver items sold in same shop. Find the average tin and copper items sold in shop D?
Answer (Detailed Solution Below)
Tabulation and Line Graph Question 2 Detailed Solution
Common Calculation
For shop A,
Number of copper items sold in shop A is 24.
Number of bronze items sold in shop A is 16.
So, total number of copper and bronze items sold in shop A is 24 + 16 = 40.
So, Ratio between total number of [ copper + bronze] items sold to number silver items sold.
So, Number of silver items sold in shop A is 40 × 4 /5 = 32
Similarly, we can calculate others values also, which is given in the table.
Shop |
Number of copper items sold |
Number of Bronze items sold |
Number of Silver items sold |
A |
24 |
16 |
32 |
B |
30 |
28 |
24 |
C |
32 |
18 |
36 |
D |
36 |
24 |
40 |
Calculation
In Shop D:
Bronze = 24, Silver = 40 ⇒ Total = 64
Tin items = 25% more than 64 = 1.25 × 64 = 80
Now, tin = 80, copper = 36
Average = (80 + 36) ÷ 2 = 116 ÷ 2 = 58
Answer: 58
Tabulation and Line Graph Question 3:
Comprehension:
The line graph shows the number of copper and bronze items sold in four different shops [A, B, C, and D].
The given table shows the ratio between total number of [ copper + bronze] items sold to number silver items sold.
Shop |
Ratio between total number of [ copper + bronze] items sold to number silver items sold. |
A |
5:4 |
B |
29:12 |
C |
25:18 |
D |
3:2 |
Find the difference between number of copper sold in shop B and C together and number of silver items sold in shop B and C together?
Answer (Detailed Solution Below)
Tabulation and Line Graph Question 3 Detailed Solution
Common Calculation
For shop A,
Number of copper items sold in shop A is 24.
Number of bronze items sold in shop A is 16.
So, total number of copper and bronze items sold in shop A is 24 + 16 = 40.
So, Ratio between total number of [ copper + bronze] items sold to number silver items sold.
So, Number of silver items sold in shop A is 40 × 4 /5 = 32
Similarly, we can calculate others values also, which is given in the table.
Shop |
Number of copper items sold |
Number of Bronze items sold |
Number of Silver items sold |
A |
24 |
16 |
32 |
B |
30 |
28 |
24 |
C |
32 |
18 |
36 |
D |
36 |
24 |
40 |
Calculation
Copper in B + C = 30 + 32 = 62
Silver in B + C = 24 + 36 = 60
Difference = 62 – 60 = 2
Answer: 2
Tabulation and Line Graph Question 4:
Comprehension:
The line graph shows the number of copper and bronze items sold in four different shops [A, B, C, and D].
The given table shows the ratio between total number of [ copper + bronze] items sold to number silver items sold.
Shop |
Ratio between total number of [ copper + bronze] items sold to number silver items sold. |
A |
5:4 |
B |
29:12 |
C |
25:18 |
D |
3:2 |
Average selling price of copper items is Rs. 750, average selling price of bronze items is Rs. 550 and average silver items is Rs. 1050 sold in shop B. Find the average (approx) selling price of all the items sold in shop B?
Answer (Detailed Solution Below)
Tabulation and Line Graph Question 4 Detailed Solution
Common Calculation
For shop A,
Number of copper items sold in shop A is 24.
Number of bronze items sold in shop A is 16.
So, total number of copper and bronze items sold in shop A is 24 + 16 = 40.
So, Ratio between total number of [ copper + bronze] items sold to number silver items sold.
So, Number of silver items sold in shop A is 40 × 4 /5 = 32
Similarly, we can calculate others values also, which is given in the table.
Shop |
Number of copper items sold |
Number of Bronze items sold |
Number of Silver items sold |
A |
24 |
16 |
32 |
B |
30 |
28 |
24 |
C |
32 |
18 |
36 |
D |
36 |
24 |
40 |
Calculation
In Shop B:
Copper = 30 × 750 = 22,500
Bronze = 28 × 550 = 15,400
Silver = 24 × 1050 = 25,200
Total value = 22,500 + 15,400 + 25,200 = 63,100
Total items = 30 + 28 + 24 = 82
Average selling price = 63100 ÷ 82 = Rs. 769.51 (approx)
Answer: Rs. 770
Tabulation and Line Graph Question 5:
Comprehension:
The line graph shows the number of copper and bronze items sold in four different shops [A, B, C, and D].
The given table shows the ratio between total number of [ copper + bronze] items sold to number silver items sold.
Shop |
Ratio between total number of [ copper + bronze] items sold to number silver items sold. |
A |
5:4 |
B |
29:12 |
C |
25:18 |
D |
3:2 |
Two types silver items sold in shop A, x and y. Number of x type silver items sold in shop A is 3m + 2 and number of y type silver items sold in shop A is 2n + 6. Sum of m and n is 10. Find the ratio between m and n?
Answer (Detailed Solution Below)
Tabulation and Line Graph Question 5 Detailed Solution
Common Calculation
For shop A,
Number of copper items sold in shop A is 24.
Number of bronze items sold in shop A is 16.
So, total number of copper and bronze items sold in shop A is 24 + 16 = 40.
So, Ratio between total number of [ copper + bronze] items sold to number silver items sold.
So, Number of silver items sold in shop A is 40 × 4 /5 = 32
Similarly, we can calculate others values also, which is given in the table.
Shop |
Number of copper items sold |
Number of Bronze items sold |
Number of Silver items sold |
A |
24 |
16 |
32 |
B |
30 |
28 |
24 |
C |
32 |
18 |
36 |
D |
36 |
24 |
40 |
Calculation
In Shop A:
Total silver items = 32
Number of x-type silver items = 3m + 2
Number of y-type silver items = 2n + 6
So,
3m + 2 + 2n + 6 = 32
⇒ 3m + 2n = 24
Also, m + n = 10,
So, m = 4 and n = 6
⇒ Required ratio m : n
Answer: m : n = 4 : 6 = 2 : 3
Top Tabulation and Line Graph MCQ Objective Questions
The table below shows the ratio of manufacturing of Car A to the manufacturing of Car B by the same company from 2012-2016.
The Line graph shows the manufacturing (in thousands) of Car A, from 2012-2016.
What is the ratio of number of Car B manufactured in 2012 to the number of Car A manufactured in 2014?
Year | Production Ratio of A to B |
2012 | 17 : 16 |
2013 | 8 :7 |
2014 | 9 : 10 |
2015 | 18 : 19 |
2016 | 7 : 6 |
Answer (Detailed Solution Below)
Tabulation and Line Graph Question 6 Detailed Solution
Download Solution PDFCalculation:
The ratio of number of car A and car B in 2012 = 17 : 16
The production of car A in 2012 = 850
Let the ratio of number of car A and car B be 17x and 16x respectively
⇒ 17x = 850
⇒ x = 50
The production of car B = 16x = 16 × 50 = 800
The number of car A manufactured in 2014 = 630
Required ratio = (800 : 630)
⇒ 80 : 63
∴ The ratio of number of Car B manufactured in 2012 to the number of Car A manufactured in 2014 is 80 : 63
Comprehension:
Directions: Study the following line graph which gives the number of students who joined and left the school in the beginning of the year for six years from 2015 to 2020.
Initial strength of the school in 2014 was 2000
Answer questions based on the line graph given below.
What is the strength of the school at the end of the year 2017?
Answer (Detailed Solution Below)
Tabulation and Line Graph Question 7 Detailed Solution
Download Solution PDFGiven :
The students joined and left in different years
Intial strength of school = 2000
Calculation :
Strength of school at the end of 2017 = 2000 + (375 - 250) + (350 - 425) + (400 - 220)
⇒ 2000 + 125 - 75 + 180 = 2230
∴ The answer is 2230.
Comprehension:
Directions: Read the data carefully and answer the questions that follow:
The following line graph shows the percentage of total employees working as a manager in Alexis Finance Limited, for the time period from the year 2003 to the year 2007.
(Note: Total number of employees = Managers + Workers)
The table shows the ratio of the number of male to female managers within the company.
Year | Male ∶ Female |
---|---|
2003 | 3 ∶ 2 |
2004 | 2 ∶ 1 |
2005 | 5 ∶ 3 |
2006 | 2 ∶ 3 |
2007 | 8 ∶ 5 |
If the total number of workers remains the same in the year 2005 and the year 2006, then find the ratio between the total number of male managers in these two years.
Answer (Detailed Solution Below)
Tabulation and Line Graph Question 8 Detailed Solution
Download Solution PDFLet the total number of employees in the the year 2005 be x
So, the total number of managers in 2005 = (80/100) × x = 0.8x
⇒ Total number of workers in 2005 = x – 0.8x = 0.2x
Hence, the number of male managers in 2005 = (5/8) × 0.8x = 0.5x
And the total number of employees in the the year 2006 be y
Also, So, the total number of managers in 2006 = (50/100) × y = 0.5y
⇒ Total number of workers in 2006 = y – 0.5y = 0.5y
Hence, the number of male managers in 2006 = (2/5) × 0.5y = 0.2y
As the number of workers is the same, we get:
0.2x = 0.5y
⇒ x = 2.5y ----(i)
Using equation(i), the required ratio will become:
(0.5 × 2.5y)/0.2y = 25/4
∴ The reuqired ratio between the number of male managers in 2005 and 2006 is 25 ∶ 4
Comprehension:
Direction: Go through the passage and line graph given below and answer the question based on it.
The line graph given below shows the number of orders placed (in thousands) and orders delivered (in thousands) during the week i.e from Monday to Saturday. The number of orders delivered was returned by some of the customers due to various reasons on the next day of the order delivered.
The percentage of orders returned is mentioned in the table below.
The returned ordered percentage represents the percentage of orders returned from the order delivered on the previous day. i.e the number of orders returned on Tuesday were returned from the order delivered on Monday and so on. Assuming that no orders were delivered and returned on Sunday. Items delivered on Saturday will return on Monday.
Days |
Returned |
---|---|
Monday |
15% |
Tuesday |
20% |
Wednesday |
27% |
Thursday |
13% |
Friday |
21% |
Saturday |
16% |
The order placed and delivered on Wednesday is what approximate percentage of the order placed and returned on Friday.
Answer (Detailed Solution Below)
Tabulation and Line Graph Question 9 Detailed Solution
Download Solution PDFFormula used:
Percentage = (Part value/Original value) × 100
Calculation:
Days |
Orders placed (in thousands) |
Orders Delivered (in thousands) |
% of orders returned |
Orders Returned (in thousands) |
Monday |
575 |
149 |
20% |
29.8 |
Tuesday |
375 |
225 |
27% |
60.75 |
Wednesday |
400 |
223 |
13% |
28.99 |
Thursday |
750 |
283 |
21% |
59.43 |
Friday |
275 |
147 |
16% |
23.52 |
Saturday |
325 |
188 |
15% |
28.2 |
Orders placed and delivered on Wednesday
⇒ 400 + 223 = 623
Orders placed and returned on Friday
⇒ 275 + 59.43
⇒ 334.43
Percentage
⇒ (623/334.43) × 100
⇒ 186.70% ≈ 186%
∴ The approximate percentage is 186%.
Comprehension:
Direction: Go through the passage and line graph given below and answer the question based on it.
The line graph given below shows the number of orders placed (in thousands) and orders delivered (in thousands) during the week i.e from Monday to Saturday. The number of orders delivered was returned by some of the customers due to various reasons on the next day of the order delivered.
The percentage of orders returned is mentioned in the table below.
The returned ordered percentage represents the percentage of orders returned from the order delivered on the previous day. i.e the number of orders returned on Tuesday were returned from the order delivered on Monday and so on. Assuming that no orders were delivered and returned on Sunday. Items delivered on Saturday will return on Monday.
Days |
Returned |
---|---|
Monday |
15% |
Tuesday |
20% |
Wednesday |
27% |
Thursday |
13% |
Friday |
21% |
Saturday |
16% |
Find the average number of items returned on Tuesday and Wednesday.
Answer (Detailed Solution Below)
Tabulation and Line Graph Question 10 Detailed Solution
Download Solution PDFCalculation:
Days |
Orders placed (in thousands) |
Orders Delivered (in thousands) |
% of orders returned |
Orders Returned (in thousands) |
Monday |
575 |
149 |
20% |
29.8 |
Tuesday |
375 |
225 |
27% |
60.75 |
Wednesday |
400 |
223 |
13% |
28.99 |
Thursday |
750 |
283 |
21% |
59.43 |
Friday |
275 |
147 |
16% |
23.52 |
Saturday |
325 |
188 |
15% |
28.2 |
Total items returned on Tuesday and Wednesday = (60.75 + 28.99) thousand = 89740
Average of items returned on Tuesday and Wednesday = 89740/2 = 44870
∴ 44870
Comprehension:
Direction: The given line graph shows the number of passengers travelled by 2 cab drivers and the table shows the percentage of females who travelled in the cabs in different months.
Month |
Driver A |
Driver B |
Percentage of Females |
Percentage of Females |
|
May |
30% |
50% |
June |
50% |
70% |
July |
20% |
40% |
August |
60% |
30% |
September |
40% |
50% |
Find the ratio of the average of the female in the month of June and July by Driver A to the average of the males in the same month by Driver B.
Answer (Detailed Solution Below)
Tabulation and Line Graph Question 11 Detailed Solution
Download Solution PDFFemales in the month June = 250 × 50/100 = 125
Females in the month July = 200 × 20/100 = 40
The average of the female in the month of June and July by Driver A = (125 + 40)/2 = 82.5
Percentage of males in the month June = 100 - 70 = 30
Males in the month June = 350 × 30/100 = 105
Percentage of males in the month of July = 100 - 40 = 60
Males in the month July = 250 × 60/100 = 150
The average of the Males in the month of June and July by Driver B = (105 + 150)/2 = 127.5
The ratio of the average of the female in the month of June and July by Driver A to the average of the males in the same month by Driver B
= 82.5 : 127.5 = 11 : 17
Comprehension:
Directions∶ Following line graph represents the population in 6 different villages (M, N, O, P, Q and R) and the tabular column represents the ratio of literate to illiterate people and also represents the percentage of the male population.
Village |
Ratio of literate to illiterate |
Percentage of male population |
M |
1 ∶ 1 |
30% |
N |
5 ∶ 4 |
40% |
O |
5 ∶ 7 |
40% |
P |
3 ∶ 5 |
50% |
Q |
2 ∶ 3 |
40% |
R |
3 ∶ 7 |
60% |
Find the average number of female population in all the villages together.
Answer (Detailed Solution Below)
Tabulation and Line Graph Question 12 Detailed Solution
Download Solution PDF
Vilage |
Total population |
% Female |
Female |
M |
3200 |
70% |
2240 |
N |
3600 |
60% |
2160 |
O |
4800 |
60% |
2880 |
P |
4000 |
50% |
2000 |
Q |
5500 |
60% |
3300 |
R |
3000 |
40% |
1200 |
Required average = Sum of observations/number of observations
∴ Required average = (2240 + 2160 + 2880 + 2000 + 3300 + 1200)/6 = 2296.67Comprehension:
Directions: Read the data carefully and answer the questions that follow:
The following line graph shows the percentage of total employees working as a manager in Alexis Finance Limited, for the time period from the year 2003 to the year 2007.
(Note: Total number of employees = Managers + Workers)
The table shows the ratio of the number of male to female managers within the company.
Year | Male ∶ Female |
---|---|
2003 | 3 ∶ 2 |
2004 | 2 ∶ 1 |
2005 | 5 ∶ 3 |
2006 | 2 ∶ 3 |
2007 | 8 ∶ 5 |
If it is known that the number of employees is the same for all the five years. Then what will be the percentage decrease in the number of male managers from the year 2005 to the year 2006?
Answer (Detailed Solution Below)
Tabulation and Line Graph Question 13 Detailed Solution
Download Solution PDFLet the number of employees in the company during each of the year be x
So, the number of managers in the year 2005 = (80/100)x = 0.8x
Among them, the number of male managers = (5/8) × 0.8x = 0.5x
Similarly,
So, the number of managers in the year 2006 = (50/100)x = 0.5x
Among them, the number of male managers = (2/5) × 0.5x = 0.2x
So, the percentage decrease in the number of male managers = [(0.5x – 0.2x)/0.5x] × 100 = 60%
Comprehension:
Directions: Read the diagram carefully and answer the following questions.
The following diagram shows the percentage of the number of orders and the percentage of delivery after the cancellation of orders by 5 delivery partners. Some values are missing in the diagram.
The table shows the number of delivered items by 5 delivery partners.
Delivery Partners |
Delivered after cancellation |
A |
- |
B |
45 |
C |
15 |
D |
- |
E |
- |
If the total number of cancelled and delivered orders of C is the same and the number of cancelled orders of C and E is in the ratio of 5 : 6. Then what will be the total number of orders placed in E?
Answer (Detailed Solution Below)
Tabulation and Line Graph Question 14 Detailed Solution
Download Solution PDFGiven: Number of delivered orders after cancellation of C = 15
Ratio of cancelled orders of C and E = 5 : 6
Total number of cancelled orders for C = Total number of delivered orders for C
Percentage of delivered orders of E = 80%
Calculation:
Number of cancelled order of C = 15
Number of cancelled order of E = 15/5 × 6 = 18
Percentage of cancelled orders of E = 20%
Total number of orders of E = 18/20 × 100 = 90
Comprehension:
Directions∶ Following line graph represents the population in 6 different villages (M, N, O, P, Q and R) and the tabular column represents the ratio of literate to illiterate people and also represents the percentage of the male population.
Village |
Ratio of literate to illiterate |
Percentage of male population |
M |
1 ∶ 1 |
30% |
N |
5 ∶ 4 |
40% |
O |
5 ∶ 7 |
40% |
P |
3 ∶ 5 |
50% |
Q |
2 ∶ 3 |
40% |
R |
3 ∶ 7 |
60% |
What is the respective ratio between total literate males from villages M, N and O and the total number of males from village P, Q and R.?
Answer (Detailed Solution Below)
Tabulation and Line Graph Question 15 Detailed Solution
Download Solution PDFCalculations:
From the line graph given, we can get the total population of villages (M, N, O, P, Q ,and R).
From the table provided, We can find 4 parameters only:
1. Literate people of a particular village (Ratio of literate to illiterate)
2. Illiterate people of a particular village (Ratio of literate to illiterate)
3. Male population of a particular village (Percentage of male population)
4. Female population of a particular village (Percentage of male population)
All Data that can be derived from the Line graph and Tabulation is summarised below.
As we can see from the data we can't infer number of literate males.
Hence, The ratio can't be determined
Individual Solution:
Total population |
% of male |
||
P |
4000 |
50% |
2000 |
Q |
5500 |
40% |
2200 |
R |
3000 |
60% |
1800 |
We can not find ratio of literate and illiterate male From M,N and O.
⇒ Male from village P, Q and R = 2000 + 2200 + 1800 = 6000
∴ The ratio can't be determined