Tabulation and Bar Graph MCQ Quiz - Objective Question with Answer for Tabulation and Bar Graph - Download Free PDF

Common Calculation

Number of males in city P, Q, R and S is 440, 600, 400 and 680 respectively.

We are given:

For each city, the ratio between the sum of male and female to the difference between male and female is provided. Also, males are more than females.

Let’s denote:

M = Number of males (given)

F = Number of females (to find)

Sum = M + F

Diff = M – F
So:

City P

Ratio = 9:2, M = 440

[ M + F] / [M – F] = 9/2

⇒ 9(M − F) = 2(M + F)

Or, 9M – 9F = 2M + 2F

So, 7M = 11F

Or, M/F = 11/7

So, M = 440, F = [440 / 11] × 7  = 280

So, Number of Females in city P is 280.

Similarly, we can calculate the others values also.

Calculation

Given:

Female population in T is 66.66% (i.e., 2/3) higher than in Q

Female population in Q = 150
⇒ Female population in T = [(150 + (2/3) × 150 = 150 + 100 = 250

Ratio of males in R and T = 8 : 9
Males in R = 400
⇒ Males in T = [9 / 8] × 400 = 450

Total population in T = Males + Females = 450 + 250 = 700

City S total population is 960​

Average total population of T and S = [700 + 960] / 2 = 1660/ 2 = 830

Common Calculation

Number of males in city P, Q, R and S is 440, 600, 400 and 680 respectively.

We are given:

For each city, the ratio between the sum of male and female to the difference between male and female is provided. Also, males are more than females.

Let’s denote:

M = Number of males (given)

F = Number of females (to find)

Sum = M + F

Diff = M – F
So:

City P

Ratio = 9:2, M = 440

[ M + F] / [M – F] = 9/2

⇒ 9(M − F) = 2(M + F)

Or, 9M – 9F = 2M + 2F

So, 7M = 11F

Or, M/F = 11/7

So, M = 440, F = [440 / 11] × 7  = 280

So, Number of Females in city P is 280.

Similarly, we can calculate the others values also.

Calculation

Educated females in P = Average of females in Q and R

= [ 150 + 120] / 2 = 270 / 2 =135

Total females in P = 280
→ Uneducated = 280 – 135 = 145
→ 3/5 are married

⇒ unmarried = 2/5 of 145 = 58

Males in R = 400

Uneducated unmarried females in P + Males in R = 58 + 400 = 458

Common Calculation

Number of males in city P, Q, R and S is 440, 600, 400 and 680 respectively.

We are given:

For each city, the ratio between the sum of male and female to the difference between male and female is provided. Also, males are more than females.

Let’s denote:

M = Number of males (given)

F = Number of females (to find)

Sum = M + F

Diff = M – F
So:

City P

Ratio = 9:2, M = 440

[ M + F] / [M – F] = 9/2

⇒ 9(M − F) = 2(M + F)

Or, 9M – 9F = 2M + 2F

So, 7M = 11F

Or, M/F = 11/7

So, M = 440, F = [440 / 11] × 7  = 280

So, Number of Females in city P is 280.

Similarly, we can calculate the others values also.

Calculation

In S: Males = 680

→ servicemen : retired = 15 : 19
Females in S = 280

→ 35% working, 65% non-working

So, Total parts = 15 + 19 = 34
→ Retired males = [ 19/34] × 680 = 380

Non-working females = 65% of 280 = 0.65×280=182

Difference = 380 – 182 = 198

Common Calculation

Number of males in city P, Q, R and S is 440, 600, 400 and 680 respectively.

We are given:

For each city, the ratio between the sum of male and female to the difference between male and female is provided. Also, males are more than females.

Let’s denote:

M = Number of males (given)

F = Number of females (to find)

Sum = M + F

Diff = M – F
So:

City P

Ratio = 9:2, M = 440

[ M + F] / [M – F] = 9/2

⇒ 9(M − F) = 2(M + F)

Or, 9M – 9F = 2M + 2F

So, 7M = 11F

Or, M/F = 11/7

So, M = 440, F = [440 / 11] × 7  = 280

So, Number of Females in city P is 280.

Similarly, we can calculate the others values also.

Calculation

Original in Q:

Males = 600

Females = 150

New:

Males = 600 + x

Females = 150 + 2x

Given:

[ 600 + x] / [150 + 2x] = 2 / 3

Or, 3(600 + x) = 2(150 + 2x)

Or, 1800 + 3x = 300 + 4x

Or, x = 1500

So, x – 300 = 1500 – 300 = 1200

Common Calculation

Number of males in city P, Q, R and S is 440, 600, 400 and 680 respectively.

We are given:

For each city, the ratio between the sum of male and female to the difference between male and female is provided. Also, males are more than females.

Let’s denote:

M = Number of males (given)

F = Number of females (to find)

Sum = M + F

Diff = M – F
So:

City P

Ratio = 9:2, M = 440

[ M + F] / [M – F] = 9/2

⇒ 9(M − F) = 2(M + F)

Or, 9M – 9F = 2M + 2F

So, 7M = 11F

Or, M/F = 11/7

So, M = 440, F = [440 / 11] × 7  = 280

So, Number of Females in city P is 280.

Similarly, we can calculate the others values also.

Calculation

Totals = 720 + 750 + 520 + 960 = 2950

Average = [2950 / 4] = 737.5

Given:

Turnover of company D = 9 lakhs

Profit of company C = 1 lakhs

Formula used:

Profit % = (Profit / CP) × 100

Calculation:

Required percentage = (1/9) × 100

⇒ 11.11 %

Hence, the correct answer is "11.11%".

Percentage of females in factory A and C together (above 40 years) = 60%

Percentage of males in factory A and C together (above 40 years) = 40%

Number of males in factory A and C together (above 40 years) = 40/100 × (50 + 110) = 64

Percentage of females in factory B and D together (above 40 years) = 50%

Percentage of males in factory B and D together (above 40 years) = 50%

Number of males in factory B and D together (above 40 years) = 50/100 × (70 + 120) = 95

∴ required ratio = 64 : 95

Total number of workers in all the factories = 200 + 400 + 340 + 320 = 1260

Total number of workers above 40 years of age = 50 + 70 + 110 + 120 = 350

∴ total number of workers in all the factories whose age is below 40 years = 1260 – 350 = 910

Total number of workers above 40 years in all the factories = 50 + 70 + 110 + 120 = 350

Number of females above 40 years in all the factories = 20% of 350 = 70

∴ required average = 70/4 = 17.5

Given:

Profit of company B = 6 lakhs

Investment of company B = 2 lakhs

Formula used:

Profit % = (Profit / CP) × 100

Calculation:

Required Profit % = (6 / 2) × 100

⇒ 3 × 100

⇒ 300%

Hence, the correct answer is "300%".

Given:

Formula used:

Average = Sum of observations/Number of observations.

Calculation:

Average number = (2200 + 1800 + 2500 + 2700 + 2900 + 3200)/6

⇒ 15300/6 = 2550

∴ The average number of students appeared for a exam per day is 2550.

Number of workers in factory D = 320

Number of workers in factory E = 320 + 20% of 320 = 384

Ratio of the number of males and females in factory E = 7 : 5

∴ required number of females = 5/12 × 384 = 160

Percentage of females in factory A and C together = 40%

Number of females in factory A and C together = 40% of (200 + 340) = 216

Percentage of males in factory B = 20%

Percentage of females in factory B = 100 – 20 = 80%

Number of females in factory B = 80% of 400 = 320

∴ Required number = 216 + 320 = 536

Number of males in factory C (above 40 years) = 30

Number of females in factory C (above 40 years) = 110 – 30 = 80

Number of males in factory A (above 40 years) = 30

Number of females in factory A (above 40 years) = 50 – 30 = 20

∴ required percentage = [(80 – 20) / 20 ] × 100 = 300%

Given:

The number of employees working in five different sectors and the respective ratio of male and female employees are given.

Calculations:

Number of employees in Q sector = 700

The number of male employees and female employees in Q sector be 5x and 9x

Total employees = (5x + 9x) = 14x

Required number of male employees in Q sector = \(\dfrac{5x}{14x}\) × 700

⇒ 5 × 50 = 250

∴ The answer is 250