Ratio and Proportion MCQ Quiz - Objective Question with Answer for Ratio and Proportion - Download Free PDF

Last updated on Jul 9, 2025

Ratio and Proportion MCQs have been pestering exam candidates for ages with their tricky solutions. Almost every examination such as UPSC, SSC CGL, Bank Exams, etc. with the Quantitative Aptitude section features Ratio and Proportion Questions Answers. The ratio is defined as the comparison of sizes of two quantities of the same unit. Proportion, on the other hand, refers to the equality of two ratios. Ratio and Proportion Objective Questions are pretty easy to solve if there’s enough practice. Solving these questions can save a lot of time in the exams. Testbook has worked on this Ratio and Proportion Quiz for best practice of the candidates. Practice these Ratio and Proportion Questions Answers which will help you in improving your speed and accuracy of solving Ratio and Proportion Objective Questions. We have also provided solutions and explanations to each question in this article. Also, find tips to solve questions faster!

Latest Ratio and Proportion MCQ Objective Questions

Ratio and Proportion Question 1:

 If 68 is the mean proportion between x and 272, what is the value of x?

  1. 17
  2. 16
  3. 15
  4. 19

Answer (Detailed Solution Below)

Option 1 : 17

Ratio and Proportion Question 1 Detailed Solution

Given:

Mean proportion = 68

x = Unknown

Second term = 272

Formula used:

If 68 is the mean proportion between x and 272, the formula used is:

Mean proportion = √(x × 272)

Calculation:

68 = √(x × 272)

⇒ 682 = x × 272

⇒ 4624 = x × 272

⇒ x = 4624 ÷ 272

⇒ x = 17

∴ The correct answer is option (1).

Ratio and Proportion Question 2:

Which of the following ratios is greatest?

  1.  41 : 64
  2. 50 : 59
  3. 40 : 70
  4. 26 : 90

Answer (Detailed Solution Below)

Option 2 : 50 : 59

Ratio and Proportion Question 2 Detailed Solution

Given:

Ratios to compare:

41 : 64, 50 : 59, 40 : 70, 26 : 90

Formula used:

Convert each ratio to decimal:

Calculations:

∴ The greatest ratio is 50 : 59.

Ratio and Proportion Question 3:

In a bag containing red, green, and pink tokens, the ratio of red to green tokens was 7 : 20, while the ratio of pink to red tokens was 15 : 12. What was the ratio of green to pink tokens?

  1. 16 : 7
  2. 19 : 12
  3. 25 : 7
  4. 11 : 5

Answer (Detailed Solution Below)

Option 1 : 16 : 7

Ratio and Proportion Question 3 Detailed Solution

Given:

Ratio of red to green tokens = 7:20

Ratio of pink to red tokens = 15:12

Formula Used:

To find the ratio of green to pink tokens, we align the ratios using the common term "red".

Calculation:

Ratio of red to green tokens = 7:20

Ratio of pink to red tokens = 15:12

First, express the ratios in terms of a common "red" count:

Let red tokens = 84 (LCM of 7 and 12)

Green tokens = (20 × 84) / 7 = 240

Pink tokens = (15 × 84) / 12 = 105

Now, find the ratio of green to pink tokens:

Green : Pink = 240 : 105

Simplify the ratio:

⇒ Green : Pink = (240 / 15) : (105 / 15)

⇒ Green : Pink = 16 : 7

The ratio of green to pink tokens is 16:7.

Ratio and Proportion Question 4:

If 3.5 : 17.4 :: 14 : x, find the value of x.

  1. 72.9
  2. 65.9
  3. 69.6
  4. 67.9

Answer (Detailed Solution Below)

Option 3 : 69.6

Ratio and Proportion Question 4 Detailed Solution

Given:

Calculations:

= = 69.6

∴ The corrcetv ansrwt is option 3.

Ratio and Proportion Question 5:

Suppose x : y = 2 : 5; y : z = 4 : 7. If ₹15,120 is distributed among x, y and z, then the amounts received by x, y and z, respectively, are (in ₹):

  1. 2,500, 5,200 and 7,420
  2. 1,920, 4,800 and 8,400
  3. 2,820, 4,500 and 7,800
  4. 2,700, 6,000 and 6,420

Answer (Detailed Solution Below)

Option 2 : 1,920, 4,800 and 8,400

Ratio and Proportion Question 5 Detailed Solution

Given:

x : y = 2 : 5

y : z = 4 : 7

Total Amount = ₹15,120

Formula used:

To combine two ratios, we use the Least Common Multiple (LCM) of the common term (y).

Final Ratio (x : y : z) = x : y : z after adjustment.

Distribution = Total Amount × (Individual ratio / Sum of all ratios)

Calculation:

x : y = 2 : 5, y : z = 4 : 7

x : y = 8 : 20, y : z = 20 : 35

⇒ Combined Ratio (x : y : z) = 8 : 20 : 35

Sum of Ratios = 8 + 20 + 35 = 63

Amount for x = ₹15,120 × (8 / 63)

⇒ Amount for x = ₹1920

Amount for y = ₹15,120 × (20 / 63)

⇒ Amount for y = ₹4800

Amount for z = ₹15,120 × (35 / 63)

⇒ Amount for z = ₹8400

∴ The amounts received by x, y, and z are ₹1920, ₹4800, and ₹8400 respectively.

The correct answer is option (2).

Top Ratio and Proportion MCQ Objective Questions

u : v = 4 : 7 and v : w = 9 : 7. If u = 72, then what is the value of w?

  1. 98
  2. 77
  3. 63
  4. 49

Answer (Detailed Solution Below)

Option 1 : 98

Ratio and Proportion Question 6 Detailed Solution

Download Solution PDF

Given:

u : v = 4 : 7 and v : w = 9 : 7

Concept Used: In this type of question, number can be calculated by using the below formulae

Calculation:

u : v = 4 : 7 and v : w = 9 : 7

To make ratio v equal in both cases

We have to multiply the 1st ratio by 9 and 2nd ratio by 7

u : v = 9 × 4 : 9 × 7 = 36 : 63 ----(i)

v : w = 9 × 7 : 7 × 7 = 63 : 49 ----(ii)

Form (i) and (ii), we can see that the ratio v is equal in both cases

So, Equating the ratios we get,

u v w = 36 63 49

u w = 36 49

When u = 72,

w = 49 × 72/36 = 98

Value of w is 98

A bag has ₹ 785 in the denomination of ₹ 2, ₹ 5 and ₹ 10 coins. The coins are in the ratio of 6 : 9 : 10. How many coins of ₹ 5 are in the bag?

  1. 60
  2. 12
  3. 45
  4. 24

Answer (Detailed Solution Below)

Option 3 : 45

Ratio and Proportion Question 7 Detailed Solution

Download Solution PDF

Given:

₹ 785 in the denomination of ₹ 2, ₹ 5 and ₹ 10 coins

The coins are in the ratio of 6 : 9 : 10

Calculation:

Let the number of coins of ₹ 2, ₹ 5 and ₹ 10 be 6x, 9x, and 10x respectively

⇒ (2 × 6x) + (5 × 9x) + (10 × 10x) = 785

⇒ 157x = 785

∴ x = 5

Number of coins of ₹ 5 = 9x = 9 × 5 = 45

∴ 45 coins of ₹ 5 are in the bag

A man has 25 paise, 50 paise and 1 Rupee coins. There are 220 coins in all and the total amount is 160. If there are thrice as many 1 Rupee coins as there are 25 paise coins, then what is the number of 50 paise coins?

  1. 60
  2. 120
  3. 40
  4. 80

Answer (Detailed Solution Below)

Option 1 : 60

Ratio and Proportion Question 8 Detailed Solution

Download Solution PDF

Given:

Total coin = 220

Total money = Rs. 160

There are thrice as many 1 Rupee coins as there are 25 paise coins.

Concept used:

Ratio method is used.

Calculation:

Let the 25 paise coins be 'x'

So, one rupees coins = 3x

50 paise coins = 220 – x – (3x) = 220 – (4x)

According to the questions,

3x + [(220 – 4x)/2] + x/4 =160

⇒ (12x + 440 – 8x + x)/4 = 160

⇒  5x + 440 = 640

⇒ 5x = 200

⇒ x = 40

So, 50 paise coins = 220 – (4x) = 220 – (4 × 40) = 60

∴ The number of 50 paise coin is 60.

If A : B = 7 : 8 and B : C = 7 : 9, then what is the ratio of A : B : C ?

  1. 56 : 49 : 72
  2. 49 : 56 : 72
  3. 56 : 72 : 49
  4. 72 : 56 : 49

Answer (Detailed Solution Below)

Option 2 : 49 : 56 : 72

Ratio and Proportion Question 9 Detailed Solution

Download Solution PDF

Given:

A : B = 7 : 8

B : C = 7 : 9

Concept:

If N is divided into a : b, then

First part = N × a/(a + b)

Second part = N × b/(a + b)

Calculation:

A/B = 7/8      ----(i)

Also B/C = 7/9      ----(ii)

Multiply equation (i) and (ii) we get,

⇒ (A/B) × (B/C) = (7/8) × (7/9)

⇒ A/C = 49/72

∵ A : B = 49 : 56

∴ A : B : C = 49 : 56 : 72

 Alternate Method

A : B = 7 : 8 = 49 : 56

B : C = 7 : 9 = 56 : 72

⇒ A : B : C = 49 : 56 : 72

If A is 25% less than B, then what will be the value of (2B - A)/A ?

  1. 5/4
  2. 3/2
  3. 3/4
  4. 5/3

Answer (Detailed Solution Below)

Option 4 : 5/3

Ratio and Proportion Question 10 Detailed Solution

Download Solution PDF

Given:

A = 75% of B

Calculation:

A = 3/4 of B

⇒ A/B = 3/4

Let the value of A be 3x and B be 4x

So (2B – A)/A = (2 × 4x – 3x)/3x

⇒ (2B – A)/A = 5x/3x

∴ (2B – A)/A = 5/3

Short Trick:

Ratio of A : B = 3 : 4

∴ (2B – A)/A = (8 – 3) /3 = 5/3

If x : y = 5 : 4, then what will be the ratio of ?

  1. 25 : 16
  2. 16 : 25
  3. 4 : 5
  4. 5 : 4

Answer (Detailed Solution Below)

Option 1 : 25 : 16

Ratio and Proportion Question 11 Detailed Solution

Download Solution PDF

Given:

x : y = 5 : 4

Explanation:

(x/y) = (5/4)

(y/x) = (4/5)

Now,  = (5/4)/(4/5) = 25/16

 = 25 : 16

How much should be added to each term of 4 : 7 so that it becomes 2 : 3?

  1. 2
  2. 3
  3. 4
  4. 1

Answer (Detailed Solution Below)

Option 1 : 2

Ratio and Proportion Question 12 Detailed Solution

Download Solution PDF

Given :

Ratio of two numbers is 4 : 7 

Calculations :

Let the number added to denominator and numerator be 'x' 

Now according to the question 

(4 + x)/(7 + x) = 2 : 3 

⇒ 12 + 3x = 14 + 2x 

⇒ x = 2 

∴ 2 will be added to make the term in the ratio of 2 : 3.

The ratio of two numbers is 14 : 25. If the difference between them is 264, then which is the smaller of the two numbers?

  1. 316
  2. 294
  3. 336
  4. 282

Answer (Detailed Solution Below)

Option 3 : 336

Ratio and Proportion Question 13 Detailed Solution

Download Solution PDF

Given:

Ratio of two numbers is 14 : 25

Difference between them is 264

Calculation:

Let the numbers be 14x and 25x

⇒ 25x – 14x = 264

⇒ 11x = 264

∴ x = 24

⇒ Smaller number = 14x = 14 × 24 = 336

∴ The smaller of the two numbers is 336.

The ratio of the salaries of Ravi and Sarita is 3 ∶ 5. If the salary of each is increased by ₹ 5,000, the new ratio becomes 29 ∶ 45. What is the present salary of Sarita?

  1. Rs. 24,000
  2. Rs. 30,000
  3. Rs. 45,000
  4. Rs. 40,000

Answer (Detailed Solution Below)

Option 4 : Rs. 40,000

Ratio and Proportion Question 14 Detailed Solution

Download Solution PDF

Given:

The ratio of the salaries of Ravi and Sarita is 3 ∶ 5.

If the salary of each is increased by ₹ 5,000, the new ratio becomes 29 ∶ 45.

Formula Used:

Initial salaries: R = 3x and S = 5x.

New salaries: R + 5000 and S + 5000.

New ratio: (R + 5000) / (S + 5000) = 29/45.

Calculation:

Substituting the values of R and S in the new ratio equation:

(3x + 5000) / (5x + 5000) = 29 / 45

Cross multiplying to solve for x:

⇒ 45 × (3x + 5000) = 29 × (5x + 5000)

⇒ 135x + 225000 = 145x + 145000

⇒ 145x - 135x = 225000 - 145000

⇒ 10x = 80000

⇒ x = 8000

Now, finding the current salary of Sarita:

S = 5x = 5 × 8000

S = 40000

The present salary of Sarita is ₹ 40,000.

Shortcut Trick 

Three-fifths of my current age is the same as five-sixths of that of one of my cousins’. My age ten years ago will be his age four years hence. My current age is ______ years.

  1. 55
  2. 45
  3. 60
  4. 50

Answer (Detailed Solution Below)

Option 4 : 50

Ratio and Proportion Question 15 Detailed Solution

Download Solution PDF

Let my current age = x years and my cousin’s age = y years.

Three-fifths of my current age is the same as five-sixths of that of one of my cousins’,

⇒ 3x/5 = 5y/6

⇒ 18x = 25y

My age ten years ago will be his age four years hence,

⇒ x – 10 = y + 4

⇒ y = x – 14,

⇒ 18x = 25(x – 14)

⇒ 18x = 25x – 350

⇒ 7x = 350

∴ x = 50 years

Hot Links: teen patti gold online teen patti game teen patti octro 3 patti rummy