Puzzle MCQ Quiz - Objective Question with Answer for Puzzle - Download Free PDF

Here, given persons D, F, H, L, M, P, R, U, V and X; and the years are 1987, 1990, 1995 and 2004.

1) More than four persons start their businesses before R.

2) X and U start their businesses in the same year which is multiple of 3.

3) The difference between starting year in which D and P starts their businesses is one – third to that of between U and F. Therefore, case 2 is eliminated.

4) V and P start their businesses before R but in different years.

5) Only one person starts his business in the same year as of M but not in leap year. Therefore, case 1(a) and case 2(a) are eliminated.

6) The difference between starting year of H and F is more than 10 years.

7) L didn't start the business in 1995.

Hence, P and M started their businesses in the year 1987.

Here, given persons D, F, H, L, M, P, R, U, V and X; and the years are 1987, 1990, 1995 and 2004.

1) More than four persons start their businesses before R.

2) X and U start their businesses in the same year which is multiple of 3.

3) The difference between starting year in which D and P starts their businesses is one – third to that of between U and F. Therefore, case 2 is eliminated.

4) V and P start their businesses before R but in different years.

5) Only one person starts his business in the same year as of M but not in leap year. Therefore, case 1(a) and case 2(a) are eliminated.

6) The difference between starting year of H and F is more than 10 years.

7) L didn't start the business in 1995.

Hence, V started his business after three years of P.

Here, given persons D, F, H, L, M, P, R, U, V and X; and the years are 1987, 1990, 1995 and 2004.

1) More than four persons start their businesses before R.

2) X and U start their businesses in the same year which is multiple of 3.

3) The difference between starting year in which D and P starts their businesses is one – third to that of between U and F. Therefore, case 2 is eliminated.

4) V and P start their businesses before R but in different years.

5) Only one person starts his business in the same year as of M but not in leap year. Therefore, case 1(a) and case 2(a) are eliminated.

6) The difference between starting year of H and F is more than 10 years.

7) L didn't start the business in 1995.

Since, each person except L started his business in the year in which maximum number of persons started their business but L started his business in the year in which only one other person started.

Hence, the odd one is L.

Here, given persons D, F, H, L, M, P, R, U, V and X; and the years are 1987, 1990, 1995 and 2004.

1) More than four persons start their businesses before R.

2) X and U start their businesses in the same year which is multiple of 3.

3) The difference between starting year in which D and P starts their businesses is one – third to that of between U and F. Therefore, case 2 is eliminated.

4) V and P start their businesses before R but in different years.

5) Only one person starts his business in the same year as of M but not in leap year. Therefore, case 1(a) and case 2(a) are eliminated.

6) The difference between starting year of H and F is more than 10 years.

7) L didn't start the business in 1995.

Since, L and F are the last person to start their businesses.

Hence, the incorrect statement is more than two persons started their business after L.

Here, given persons D, F, H, L, M, P, R, U, V and X; and the years are 1987, 1990, 1995 and 2004.

1) More than four persons start their businesses before R.

2) X and U start their businesses in the same year which is multiple of 3.

3) The difference between starting year in which D and P starts their businesses is one – third to that of between U and F. Therefore, case 2 is eliminated.

4) V and P start their businesses before R but in different years.

5) Only one person starts his business in the same year as of M but not in leap year. Therefore, case 1(a) and case 2(a) are eliminated.

6) The difference between starting year of H and F is more than 10 years.

7) L didn't start the business in 1995.

Since, M and V started their businesses in different years. Therefore, statement A is incorrect.

V and D started their businesses in same year. Therefore, statement B is incorrect.

V and L started their businesses in different year. Therefore, statement C is correct.

Hence, the correct answer is both 2 and 4.

Let my current age = x years and my cousin’s age = y years.

Three-fifths of my current age is the same as five-sixths of that of one of my cousins’,

⇒ 3x/5 = 5y/6

⇒ 18x = 25y

My age ten years ago will be his age four years hence,

⇒ x – 10 = y + 4

⇒ y = x – 14,

⇒ 18x = 25(x – 14)

⇒ 18x = 25x – 350

⇒ 7x = 350

∴ x = 50 years

Let,

Price of one pen = x

Price of one notebook = y

Given:

1) Mohit bought 3 pens and 6 notebooks by paying an amount of Rs. 180

=> 3x + 6y = 180

=> 3x = 180 – 6y

=> x = (180 – 6y) ÷ 3

=> x = 60 – 2y --------------- (i)

2) Sudesh bought 5 pens and 2 notebooks by paying an amount of Rs. 116

=> 5x + 2y = 116

Putting the value of x from eq (i)

=> 5(60 – 2y) + 2y = 116

=> 300 – 10y + 2y = 116

=> 300 – 116 = 10y – 2y

=> 8y = 184

=> y = 23

Mohit spend on buying 6 notebooks

=> 6y = 6 × 23 = 138

Hence, Mohit spend “Rs. 138” on buying notebooks.

According to the question, after interchanging the given two signs and two numbers i.e :

• × and +
• Two numbers 3 and 9

So,

I. 7 + 3 – 8 ÷ 2 × 9

⇒ 7 + 3 - 4 × 9

⇒ 7 + 3 - 36

⇒ 10 - 36

⇒ -26

II. 4 + 3 – 9 × 8 ÷ 2

⇒ 4 + 3 - 9 × 4

⇒ 4 + 3 - 36

⇒ 7 - 36

⇒ -29

Let the age of father be F and that of son be S.

F + S = 50 (Given)

S = 50 – F     _____ (i)

Six years back father's age was 6 more than thrice his son's age.

According to problem:

(F – 6) = 3(S – 6) + 6     _____ (ii)

Substituting the value of equation (i) in (ii), we get:

F – 6 = 3(50 – F – 6) + 6

⇒ F – 6 = 3(44 – F) + 6

⇒ F – 6 = 132 – 3F + 6

⇒ F + 3F = 132 + 6 + 6

⇒ 4F = 144

⇒ F = 144/4

⇒ F = 36

So, father's age 6 years hence = (36 + 6) = 42

Hence, ‘42’ is the correct answer.

The logic followed here is:

1) 15 → 12 + 3 = 15 kg

2) 20 → 12 + 8 = 20 kg

3) 23 → 12 + 8 + 3 = 23 kg

4) 21 → It CANNOT be the total weight, in kg, of any combination of these boxes.

Hence, ‘21’ is the correct answer.

Let the number of bulls be ‘a’ and the number of hens be ‘b’.

So, the total numbers of heads are (a + b) and total numbers of legs are (4a + 2b).

According to question:

(4a + 2b) = 2(a + b) + 48

4a + 2b = 2a + 2b + 48

4a + 2b – 2a – 2b = 48

2a = 48

a = 24

So, the number of bulls is 24.

Hence, ‘24’ is the correct answer.

Given:

A side of a square-shaped park is 12 m.

• If a square-shaped garden with a side of 24 m is developed around the park, then the garden with the park will look like the picture below:

Formula:

Area of square = Side × Side

Calculation:

=> Total area of the park including the garden = Area of the outer square = 24 × 24

=> Area of square = 576 m2

Hence, the total area of the park including the garden is 576 m².

Let the present age of Anamika be A, Malini be M and that of Srinidhi be S.

The, according to the question:

1) Seven years from now, Anamika will be as old as Malini was 4 years ago. 

A + 7 = M - 4

⇒ M = A + 11

S = 2 years

And, 

2) Srinidhi was born 2 years ago. The average age of Anamika, Malini and Srinidhi 10 years from now will be 33 years.

A + M + S = 99 - 30

A + M + S = 69 

Now, by substituting the above values,

A + (A + 11) + 2 = 69 

2A + 13 = 69

A = 56 ÷ 2

A = 28 years

Hence, the present age of Anamika is 28 years is the correct answer.

For this question, We have to check the given equation as-

146 –  2 + 3 × 123 × 5 + 2

New equation after replacing symbols-

146 ÷ 2 × 3 – 123 - 5 × 2

According to the BODMAS rule-

⇒ 73 × 3 –  123 – 5 × 2

⇒ 219 –  123 –  10

⇒ 86

Hence, Option (4) is correct.

BODMAS Table: 

Given equation I: 55 + 42 – 36 × 20 ÷ 9 = 17

Now, if '20 and 36' are interchanged, then:

⇒ 55 + 42 – 20 × 36 ÷ 9 = 17

⇒ 55 + 42 – 20 × 4 = 17

⇒ 55 + 42 – 80 = 17

⇒ 97 – 80 = 17

= 17 = 17.

LHS = RHS.

Given equation II: 20 ÷ 2 × 36 + 81 – 41 = 400

Now, if '20 and 36' are interchanged, then:

⇒ 36 ÷ 2 × 20 + 81 – 41 = 400

⇒ 18 × 20 + 81 – 41 = 400

⇒ 360 + 81 – 41 = 400

⇒ 441 – 41 = 400

= 400 = 400

LHS = RHS.

Here, Both I and II are correct equation after interchanging the given symbol.

Hence, the correct answer is "Option 3".