Puzzle MCQ Quiz - Objective Question with Answer for Puzzle - Download Free PDF

1) Movie K is displayed on Monday.

2) Two movies are displayed between N and P.

3) L is displayed just one day after P. (According to this statement it is cleared that P is displayed in Tuesday.

4) M is displayed on the remaining days that is Thursday.

So, there are three movies displayed before M.

Given equation is → 16 * 6 * 4 * 24

After replacing the signs from left to right and using the BODMAS rule,

Option 1 → = ÷ ÷

16 = 6 ÷ 4 ÷ 24

16 = 1.5 ÷ 24

16 ≠ 0.0625

Option 2 → × ÷ =

16 × 6 ÷ 4 = 24

16 × 1.5 = 24

24 = 24

Option 3 → × = ÷

16 × 6 = 4 ÷ 24

16 × 6 = 0.166

96 ≠ 0.166

Option 4 → ÷ = ×

16 ÷ 6 = 4 × 24

2.666 = 4 × 24

2.666 ≠ 96

Hence, the correct answer is "Option 2".

Decoding the information, 

Given:

8900 α 100 ⊕ 5 θ 4 ⊕ 121 α 11 = ?

After replacing the signs from left to right and using the BODMAS rule,

= 8900 ÷ 100 - 5 × 4 - 121 ÷ 11

= 89 - 5 × 4 - 11

= 89 - 20 - 11

= 89 - 31

= 58

Hence, “58” is the correct answer.

Given Equation: 22 + 18 - 3 % 5 = ?

BODMAS Rule:

Decoding the given information:

Now replacing the sign from left to right using BODMAS Rule, we get:

⇒ 22 - 18 ÷ 3 × 5 = ?

⇒ 22 - 6 × 5 = ? 

⇒ 22 - 30 = 8

Hence, the correct option is "Option 2".

Here, we use the table given below:

As per the given information:

Given expression:

256 × 8 ÷ 24 + 6 - 152

After changing the sign as per the table:

256 ÷ 8 - 24 × 6 + 152

Apply BODMAS:

256 ÷ 8 - 24 × 6 + 152
32 - 24 × 6 + 152

32 - 144 + 152

184 - 144 = 40

256 ÷ 8 - 24 × 6 + 152 = 40

Hence, the correct answer is "40".

Let my current age = x years and my cousin’s age = y years.

Three-fifths of my current age is the same as five-sixths of that of one of my cousins’,

⇒ 3x/5 = 5y/6

⇒ 18x = 25y

My age ten years ago will be his age four years hence,

⇒ x – 10 = y + 4

⇒ y = x – 14,

⇒ 18x = 25(x – 14)

⇒ 18x = 25x – 350

⇒ 7x = 350

Let,

Price of one pen = x

Price of one notebook = y

Given:

1) Mohit bought 3 pens and 6 notebooks by paying an amount of Rs. 180

=> 3x + 6y = 180

=> 3x = 180 – 6y

=> x = (180 – 6y) ÷ 3

=> x = 60 – 2y --------------- (i)

2) Sudesh bought 5 pens and 2 notebooks by paying an amount of Rs. 116

=> 5x + 2y = 116

Putting the value of x from eq (i)

=> 5(60 – 2y) + 2y = 116

=> 300 – 10y + 2y = 116

=> 300 – 116 = 10y – 2y

=> 8y = 184

=> y = 23

Mohit spend on buying 6 notebooks

=> 6y = 6 × 23 = 138

According to the question, after interchanging the given two signs and two numbers i.e :

• × and +
• Two numbers 3 and 9

So,

I. 7 + 3 – 8 ÷ 2 × 9

⇒ 7 + 3 - 4 × 9

⇒ 7 + 3 - 36

⇒ 10 - 36

⇒ -26

II. 4 + 3 – 9 × 8 ÷ 2

⇒ 4 + 3 - 9 × 4

⇒ 4 + 3 - 36

⇒ 7 - 36

⇒ -29

Let the age of father be F and that of son be S.

F + S = 50 (Given)

S = 50 – F     _____ (i)

Six years back father's age was 6 more than thrice his son's age.

According to problem:

(F – 6) = 3(S – 6) + 6     _____ (ii)

Substituting the value of equation (i) in (ii), we get:

F – 6 = 3(50 – F – 6) + 6

⇒ F – 6 = 3(44 – F) + 6

⇒ F – 6 = 132 – 3F + 6

⇒ F + 3F = 132 + 6 + 6

⇒ 4F = 144

⇒ F = 144/4

⇒ F = 36

So, father's age 6 years hence = (36 + 6) = 42

Hence, ‘42’ is the correct answer.

The logic followed here is:

1) 15 → 12 + 3 = 15 kg

2) 20 → 12 + 8 = 20 kg

3) 23 → 12 + 8 + 3 = 23 kg

4) 21 → It CANNOT be the total weight, in kg, of any combination of these boxes.

Let the number of bulls be ‘a’ and the number of hens be ‘b’.

So, the total numbers of heads are (a + b) and total numbers of legs are (4a + 2b).

According to question:

(4a + 2b) = 2(a + b) + 48

4a + 2b = 2a + 2b + 48

4a + 2b – 2a – 2b = 48

2a = 48

a = 24

So, the number of bulls is 24.

Hence, ‘24’ is the correct answer.

Given:

A side of a square-shaped park is 12 m.

• If a square-shaped garden with a side of 24 m is developed around the park, then the garden with the park will look like the picture below:

Formula:

Area of square = Side × Side

Calculation:

=> Total area of the park including the garden = Area of the outer square = 24 × 24

=> Area of square = 576 m2

Let the present age of Anamika be A, Malini be M and that of Srinidhi be S.

The, according to the question:

1) Seven years from now, Anamika will be as old as Malini was 4 years ago. 

A + 7 = M - 4

⇒ M = A + 11

S = 2 years

And, 

2) Srinidhi was born 2 years ago. The average age of Anamika, Malini and Srinidhi 10 years from now will be 33 years.

\({(A + 10 + M + 10 + S + 10) \over 3} = 33 \)

\(A + M + S + 30 = 33 \times 3\)

A + M + S = 99 - 30

A + M + S = 69 

Now, by substituting the above values,

A + (A + 11) + 2 = 69 

2A + 13 = 69

A = 56 ÷ 2

A = 28 years

Hence, the present age of Anamika is 28 years is the correct answer.

For this question, We have to check the given equation as-

146 –  2 + 3 × 123 × 5 + 2

New equation after replacing symbols-

146 ÷ 2 × 3 – 123 - 5 × 2

According to the BODMAS rule-

⇒ 73 × 3 –  123 – 5 × 2

⇒ 219 –  123 –  10

⇒ 86

Hence, Option (4) is correct.

BODMAS Table: 

Given equation I: 55 + 42 – 36 × 20 ÷ 9 = 17

Now, if '20 and 36' are interchanged, then:

⇒ 55 + 42 – 20 × 36 ÷ 9 = 17

⇒ 55 + 42 – 20 × 4 = 17

⇒ 55 + 42 – 80 = 17

⇒ 97 – 80 = 17

= 17 = 17.

LHS = RHS.

Given equation II: 20 ÷ 2 × 36 + 81 – 41 = 400

Now, if '20 and 36' are interchanged, then:

⇒ 36 ÷ 2 × 20 + 81 – 41 = 400

⇒ 18 × 20 + 81 – 41 = 400

⇒ 360 + 81 – 41 = 400

⇒ 441 – 41 = 400

= 400 = 400

LHS = RHS.

Here, Both I and II are correct equation after interchanging the given symbol.

Hence, the correct answer is "Option 3".