Which one of the following statements is correct for the given system?

\(y(n) = {x^2}(n) + \frac{1}{{{x^2}(n - 1)}}\)

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UPSC ESE Electronics & Communication 2022 Official Paper
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  1. The given system is linear, non-causal and shift-variant.
  2. The given system is non-linear, causal and shift-invariant.
  3. The given system is non-linear, causal and shift-variant.
  4. The given system is linear, non-causal and shift-invariant.

Answer (Detailed Solution Below)

Option 2 : The given system is non-linear, causal and shift-invariant.
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Detailed Solution

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For Linear System :

System must satisfy additivity and homogeneity.

for input x1(n) : 

\(y_1(n) = {x_1^2}(n) + \frac{1}{{{x_1^2}(n - 1)}}\)

for input x2(n)

\(y_2(n) = {x_2^2}(n) + \frac{1}{{{x_2^2}(n - 1)}}\)

for input x(n) = x1(n) + x2(n)

\(y(n) = {[x_1(n)+x_2(n)]^2} + \frac{1}{{[x_1(n-1)+x_2(n-1)]^2}}\)

y(n) \(\neq\) y1(n)+y2(n) 

Hence Not Linear.

The present output depends on present and past values of input hence causal system.

Time Invariance :

For delayed input x(n-t)

\(y_1(n) = {x_1^2}(n-t) + \frac{1}{{{x_1^2}(n - t-1)}}\)

For delayed output y (n-t)

\(y(n-t) = {x_1^2}(n-t) + \frac{1}{{{x_1^2}(n - t-1)}}\)

y(n-t) = y1(n)

Hence Time/Shift-Invariant System.

 

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