Which of the following is solution of the integral ∫(2x2 + ex) dx?

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Bihar STET Paper I: Mathematics (Held In 2019 - Shift 1)
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  1. \(\frac{2}{3}\)x3 + ex + c
  2. \(​\frac{3}{2}\)x3 + ex + c
  3. \(​\frac{2}{3}\)x2 + ex + c
  4. none of these

Answer (Detailed Solution Below)

Option 1 : \(\frac{2}{3}\)x3 + ex + c
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Detailed Solution

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Given:

Integral to solve = ∫(2x2 + ex) dx

Concept used:

To solve the integral of a sum of functions, we can integrate each term separately.

Calculation:
  
⇒ ∫(2x2 + ex) dx = ∫2x2 dx + ∫ex dx

⇒ ∫2x2 dx = (2/3)x3 + C (where C is the constant of integration).

⇒ ∫ex dx = ex + C 

⇒ ∫(2x2 + ex) dx = (2/3)x3 + ex + C

∴ The solution to the integral ∫(2x2 + ex) dx is (2/3)x3 + ex + C.

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