Question
Download Solution PDFUnit of thermal diffusivity in SI units system
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFExplanation:
Thermal diffusivity:
Thermal diffusivity of material is given as \(α = \frac{k}{{ρ c}}\)
where k is thermal conductivity in W/m-k, ρ is density in kg/m3 and c specific heat capacity in J/kg-K
It is the property of the material. The larger the value of α, the faster heat will diffuse through the material. A high value of α could result either from a high value of thermal conductivity or low value of thermal heat capacity ρc. Thermal diffusivity α has units of square meters per second.
unit of \(\alpha =\frac{\frac{W}{m-K}}{\frac{kg}{m^3}\frac{J}{kg-K}}=\frac{m^2}{s}\)as Watt is J/s.
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